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Valentin [98]
4 years ago
6

A manager is considering three new machines for filling boxes of cereal at a processing plant. Each of the three machines is ass

igned to 10 randomly selected employees. The time required to fill 25 boxes using the machine is recorded. How many treatments does this single-factor experiment have?
a. 3
b. 10
c. 1
d. 25
Mathematics
1 answer:
Solnce55 [7]4 years ago
3 0

Answer:

3

Step-by-step explanation:

Given that a manager is considering three new machines for filling boxes of cereal at a processing plant. Each of the three machines is assigned to 10 randomly selected employees

Here the treatments are the no of machines. i.e. three machines are three treatment.

After selecting treatments 25 boxes using each machine is recorded.

Hence this is a one factor anova with three factors namely three machines affecting the result

Hence no of treatments = 3

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Margie saves $7.25 of her allowance each week. Write an expression to represent the situation
Sophie [7]

Answer:

\displaystyle 7,25w

Step-by-step explanation:

Now, $7,25 <em>per</em><em> </em><em>week</em><em> </em>indicates multiplication:

\displaystyle 7,25w

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4 0
3 years ago
Please identify whether the relation below models a proportional relationship
nikitadnepr [17]

Yes because a propprtion is 2 numbers under each other like 12 is under 8 like a fraction form.

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X + (y + 2) = (x + y) + z.<br> A. False<br> B. True
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A .
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3 years ago
The product of a number and 7, increased<br> by three.
katovenus [111]

Answer:

7x+3

Step-by-step explanation:

Hi there!

Let "a number" equal <em>x</em>.

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7x

Now, increasing by 3 just means we need to add 3:

7x+3

I hope this helps!

5 0
3 years ago
A jar contains 12 red marbles numbered 1 to 12 and 6 blue marbles numbered 1 to 6. A marble is drawn at random from the jar. Fin
lora16 [44]

Answer:

(a)P(Red)=\dfrac{2}{3}\\(b)P(Odd) =\dfrac{1}{2}\\(c)P(\text{Red or Odd Numbered})=\dfrac{5}{6}\\(d)P(\text{Blue or Even Numbered})=\dfrac{2}{3}

Step-by-step explanation:

Number of Red Marbles{1,2,3,4,5,6,7,8,9,10,11,12},n(R)=12

Number of Blue Marbles{1,2,3,4,5,6},n(B)=6

Total Number of Marbles, n(S)=6+12=18

(a)Probability that the Marble is Red

P(R)=\dfrac{n(R)}{n(S)} =\dfrac{12}{18} =\dfrac{2}{3}

(b)Probability that the marble is odd-numbered.

Number of Odd-Numbered Balls, n(O)=9

P(Odd)=\dfrac{n(O)}{n(S)} =\dfrac{9}{18} =\dfrac{1}{2}

(c)Probability that the marble is red or odd-numbered.

n(Red)=12

n(Odd Numbered marbles)=9

n(Red and Odd Numbered Marbles)=6

P(\text{Red or Odd Numbered})=P(Red)+P(Odd\:Numbered)-P(\text{Red and Odd Numbered)}\\=\dfrac{12}{18} +\dfrac{9}{18}-\dfrac{6}{18}  =\dfrac{15}{18}\\P(\text{Red or Odd Numbered})=\dfrac{5}{6}(d)Probability that the marble is blue or even-numbered.

n(Blue)=6

n(Even Numbered marbles)=9

n(Blue and Even Numbered Marbles)=3

P(\text{Blue or Even Numbered})=P(Blue)+P(Even\:Numbered)-P(\text{Blue and Even Numbered)}\\=\dfrac{6}{18} +\dfrac{9}{18}-\dfrac{3}{18}  =\dfrac{12}{18}\\P(\text{Blue or Even Numbered})=\dfrac{2}{3}

5 0
3 years ago
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