For this case we have to, so that both runners finish at the same time, Dave must also reach 88 seconds.
![Dave\ runs\ to\ \frac {440} {55} = 8\ yards\ per\ second\\Jack\ runs\ to\ \frac {440} {88} = 5\ yards\ per\ second](https://tex.z-dn.net/?f=Dave%5C%20runs%5C%20to%5C%20%5Cfrac%20%7B440%7D%20%7B55%7D%20%3D%208%5C%20yards%5C%20per%5C%20second%5C%5CJack%5C%20runs%5C%20to%5C%20%5Cfrac%20%7B440%7D%20%7B88%7D%20%3D%205%5C%20yards%5C%20per%5C%20second)
With respect to the times we have:
![88-55 = 33](https://tex.z-dn.net/?f=88-55%20%3D%2033)
Dave must have a 33-second disadvantage.
This means that in those 33 seconds of difference Jack runs:
![5 * 33 = 165 \ yards](https://tex.z-dn.net/?f=5%20%2A%2033%20%3D%20165%20%5C%20yards)
So, Dave must lose 165 yards to get to Jack
Answer:
165
To find Emma's profit, you will calculate her cost for all the items and the amount of money she collected when she resold the items.
Subtract the two amounts to find her profit or how much money she made when she sold them.
Amount Emma paid: (2 x 35) + (3 x 75) + (5 x 4) = $315
Amount the items sold for: (2 x 65) + (3 x 136) + (5 x 15) = $613
$613 - $315 = $298
Emma made $298 in profit on her items.
Answer:
£152.
Step-by-step explanation:
We have been given that a bottle contains 255 coins. 1/3 of the coins are £1.00.
Let us find 1/3 of 255 to find the number of £1 coins.
![\£1\text{ coins}=\frac{1}{3}\times 255](https://tex.z-dn.net/?f=%5C%C2%A31%5Ctext%7B%20coins%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%20255)
This means we have £85.
We are also told that 110 of the coins are 50 p coins.
![\text{Value of 50 p coins}=\£0.50\times 110](https://tex.z-dn.net/?f=%5Ctext%7BValue%20of%2050%20p%20coins%7D%3D%5C%C2%A30.50%5Ctimes%20110)
![\text{Value of 50 p coins}=\£55](https://tex.z-dn.net/?f=%5Ctext%7BValue%20of%2050%20p%20coins%7D%3D%5C%C2%A355)
Let us figure out number of 20 p coins by subtracting the number of £1 coins and 50 p coins from 255.
![\text{Number of 20 p coins}=255-(85+110)](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%2020%20p%20coins%7D%3D255-%2885%2B110%29)
![\text{Number of 20 p coins}=255-(195)](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%2020%20p%20coins%7D%3D255-%28195%29)
![\text{Number of 20 p coins}=60](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%2020%20p%20coins%7D%3D60)
![\text{Value of 20 p coins}=\£0.20\times 60](https://tex.z-dn.net/?f=%5Ctext%7BValue%20of%2020%20p%20coins%7D%3D%5C%C2%A30.20%5Ctimes%2060)
![\text{Value of 20 p coins}=\£12](https://tex.z-dn.net/?f=%5Ctext%7BValue%20of%2020%20p%20coins%7D%3D%5C%C2%A312)
Now let us find total value of the coins contained in the bottle by adding the values of £1 coins, 50 p coins and 20 p coins.
![\text{The total value of the coins}=\£85+\£55+\£12](https://tex.z-dn.net/?f=%5Ctext%7BThe%20total%20value%20of%20the%20coins%7D%3D%5C%C2%A385%2B%5C%C2%A355%2B%5C%C2%A312)
![\text{The total value of the coins}=\£152](https://tex.z-dn.net/?f=%5Ctext%7BThe%20total%20value%20of%20the%20coins%7D%3D%5C%C2%A3152)
Therefore, the total value of the coins contained in the bottle is £152.
Answer:
2. is the correct one
Step-by-step explanation:
4x-3x^3+2
Answer:
d = -3
8x3 = 24
but this one is negative so just add a - to your answers