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4 years ago

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Chemistry

1 answer:

Vlad1618 [11]4 years ago

4 0

Answer:

CH3Cl + Cl2 -> CH2ClCH2Cl + HCl

Explanation:

Chlorination is an addition reaction that involves addition of Chlorine to a chemical compound. Methane undergo addition reaction with chlorine to produce chloromethane, which undergo further further chlorination to produce dichloromethane.

For the chlorination of methane, one of the hydrogen atoms of methane is replaced by a chlorine atom of the chlorine gas (molecule)

CH4 + Cl2 -> CH3Cl + HCl

methane chlorine chloromethane Hydrochloric acid

Using their structure:

H H

I I

H - C - H + Cl - Cl -> H - C - Cl + HCl

I I

H H

methane chloromethane

In further chlorination of chloromethane, one of the hydrogen atom of chloromethane is replaced by the chlorine atom in the chlorine gas (molecule)

Chlorination of Chloromethane to dichloromethane is represented below:

CH3Cl + Cl2 -> CH2ClCH2Cl + HCl

Chloromethane Chlorine dichloromethane Hydrochloric acid

Using their structure:

Cl Cl

I I

H - C - H + Cl - Cl -> H - C - Cl + HCl

I I

H H

Chloromethane chlorine dichloromethane

Organic compound Inorganic compound

From the chemical equation above, an organic compound (Chloromethane) reacts with an inorganic compound (Chlorine) .

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At 25◦C and atmospheric pressure the volume change of mixing of binary liquid mixtures of species 1 and 2 is given by)2545(2121x

lions [1.4K]

The question is incomplete. The complete question is:

At 25◦C and atmospheric pressure the volume change of mixing of binary liquid mixtures of species 1 and 2 is given by the equation:

ΔV = x1x2(45x1 + 25x2)

Where ΔV is in cm3-mol-1. At these conditions, the molar volumes of pure liquid 1 and 2 are V1= 110 and V2= 90 cm3-mol-1. Determine the partial molar volumes 1VE and 2VE in a mixture containing 40 mole percent of specie 1.

Answer:

1VE = 117.92 cm³.mol⁻¹, 2VE = 97.92 cm³.mol⁻¹

Explanation:

In the equation given, x represents the molar fraction of each substance, thus x1 = 0.4 and x2 = 0.6. Because of the mixture, the molar partial volume of each substance will change by a same amount, which will be:

ΔV = 0.4*0.6(45*0.4+ 25*0.6)

ΔV = 7.92 cm³.mol⁻¹

1VE - V1 = 7.92

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