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3 years ago

PLEASE HELP FAST! ITS EASY! WILL GIVE BRAINLIEST!

Mathematics

1 answer:

abruzzese [7]3 years ago

6 0

Answer:

160 kilometers per hour

9560 kilometers per minute

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The function h (d) = 2d + 4.3 relates the height (h) of the water in a fountain in feet to the diameter (d) of the pipe carrying

mezya [45]

Answer:

h(1.5) = 7.3 ft

h(10.3) = 24.9 ft

Step-by-step explanation:

Given the function h(d) = 2d + 4.3,

where:

h = height of the water in a fountain (in feet)

d = diameter of the pipe carrying the water (in inches)

Substitute the input value of d = 1.5, into the function:

h(1.5) = 2(1.5) + 4.3

h(1.5) = 3 + 4.3

h(1.5) = 7 feet

The height of the water in a fountain is 7 feet when the diameter of the pipe is 1.5 inches.

Substitute the input value of d = 10.3, into the function:

h(10.3) = 2(10.3) + 4.3

h(10.3) = 20.6 + 4.3

h(10.3) = 24.9 feet

The height of the water in a fountain is 24.9 feet when the diameter of the pipe is 10.3 inches.

<h3>Context of the solutions to h(1.5) and h(10.3):</h3>

The solutions to both functions show the relationship between the diameter of the pipe to the height of the water in a fountain. The height of the water in fountain increases relative to the diameter of the pipe. In other words, as the diameter or the size of the pipe increases or widens, the height of the water in a fountain also increases.

3 0

2 years ago

Solve for n , S = (n - 2)180

pogonyaev

S=(n-2)180
Dived 180 both sides
S/180=n-2 add 2 both sides
S/180+2=n
S over 182=n
Hope this helps good luck have a nice nite

7 0

3 years ago

Which problem situation can be represented by the equation below?

olasank [31]

I believe the answer is H,
Karen had a gift card for $150. She bought 3 gifts for her sister. The gifts cost the same amount, X. After paying for the gifts, her card had a balance of $60. How much did each gift cost?

5 0

3 years ago

Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights

krok68 [10]

Answer:

Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are $\frac{6}{8}, \frac{1}{4}, \frac{1}{6}$ that are 0.75, 0.25 and 0.17 respectively.