A direct-coupled amplifier has a low-frequency gain of 40 dB, poles at 2 MHz and 20 MHz, a zero on the negative real axis at 200
MHz, and another zero at infinite frequency. Express the amplifier gain function in the form of Equations and sketch a Bode plot for the gain magnitude. What do you estimate the 3-dB frequency fH to be?
1 answer:
Answer:
Explanation:
Low frequency gain is= 40db= 20logK=>100 poles at 2MHz,20MHz
Zero at -200MHz, zero at infinity.
A) A(s) = 100FH(s)
B) Poles (1): 2 pi × 2 × 10^6= 4pi × 10^6MHz
(2): 2pi × 20 × 10^6= 4pi × 10^6 MHz
Zeroed: 2pi × 10^6 × 200= 400pi × 10^6, at infinity.
T/(S) = (1 + S/400π × 10^6)/S(1 + S/4π × 10^6)(1 + S/4π × 10^6)
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Answer:
a) Mechanical efficiency ()=63.15% b) Temperature rise= 0.028ºC
Explanation:
For the item a) you have to define the mechanical power introduced (Wmec) to the system and the power transferred to the water (Pw).
The power input (electric motor) is equal to the motor power multiplied by the efficiency. Thus, .
Then, the power transferred (Pw) to the fluid is equal to the flow rate (Q) multiplied by the pressure jump . So
.
The efficiency is defined as the ratio between the output energy and the input energy. Then, the mechanical efficiency is
For the b) item you have to consider that the inefficiency goes to the fluid as heat. So it is necessary to use the equation of the heat capacity but in a "flux" way. Calling <em>H</em> to the heat transfered to the fluid, the specif heat of the water and the density of the water:
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Finally, the temperature rise is: