All categories

3 years ago

IF IT REQUIRES A STEADY FORCE

Engineering

1 answer:

ELEN [110]3 years ago

7 0

Answer:

i believe it is 1625 newtons

Explanation:

I could be wrong but im assuming that it is 325 newtons per meter if not then the answer could be completely different

mark brainliest if you could

You might be interested in

What is the reason for the development of new construction of materials for human use? (Select all that apply.)

salantis [7]

Answer:

All 4 could be justified.

Explanation:

They all represent ultimate improvement.

7 0

3 years ago

A 1000 W iron utilizes a resistance wire which is 20 inches long and has a diameter of 0.08 inches. Determine the rate of heat g

SSSSS [86.1K]

Answer:

The rate of heat generation in the wire per unit volume is 5.79×10^7 Btu/hrft^3

Heat flux is 9.67×10^7 Btu/hrft^2

Explanation:

Rate of heat generation = 1000 W = 1000/0.29307 = 3412.15 Btu/hr

Area (A) = πD^2/4

Diameter (D) = 0.08 inches = 0.08 in × 3.2808 ft/39.37 in = 0.0067 ft

A = 3.142×0.0067^2/4 = 3.53×10^-5 ft^2

Volume (V) = A × Length

L = 20 inches = 20 in × 3.2808 ft/39.37 in = 1.67 ft

V = 3.53×10^-5 × 1.67 = 5.8951×10^-5 ft^3

Rate of heat generation in the wire per unit volume = 3412.15 Btu/hr ÷ 5.8951×10^-5 ft^3 = 5.79×10^7 Btu/hrft^3

Heat flux = 3412.15 Btu/hr ÷ 3.53×10^-5 ft^2 = 9.67×10^7 Btu/hrft^2

3 0

3 years ago

A 100 ft long steel wire has a cross-sectional area of 0.0144 in.2. When a force of 270 lb is applied to the wire, its length in

blondinia [14]

Answer:

(a) The stress on the steel wire is 19,000 Psi

(b) The strain on the steel wire is 0.00063

Explanation:

Given;

length of steel wire, L = 100 ft

cross-sectional area, A = 0.0144 in²

applied force, F = 270 lb

extension of the wire, e = 0.75 in

Part (A) The stress on the steel wire;

δ = F/A

= 270 / 0.0144

δ = 18750 lb/in² = 19,000 Psi

Part (B) The strain on the steel wire;

σ = e/ L

L = 100 ft = 1200 in

σ = 0.75 / 1200

σ = 0.00063

Part (C) The modulus of elasticity of the steel

E = δ/σ

= 19,000 / 0.00063

E = 30,000,000 Psi

4 0

3 years ago

If you measure 0.7 V across a diode, the diode is probably made of

tatuchka [14]

Answer:

Made of Silicon.

Explanation:

A diode is a semiconductor device use in mostly electronic appliances. It is two terminals device consisting of a P-N junction formed either in Germanium or silicon crystal.

Diode can be forward biased or reverse biased.

When a diode is forward biased and the applied voltage is increased from zero, hardly any current flows through the device in the beginning.

It is so because the external voltage is being opposed by the internal barrier voltage whose value is 0.7v for silicon and 0.3v for germanium.

If you measure 0.7 V across a diode, the diode is probably therefore made of Silicon.

6 0

3 years ago

An amplifier which needs a high input resistance and a high output resistance is : Select one: a. A voltage amplifier b. None of

True [87]

Answer:

None of these

Explanation:

There are different types of amplifiers, and each has different characteristics.

Voltage amplifier needs high input and low output resistance.

Current amplifier needs Low Input and High Output resistance.

Trans-conductance amplifier Low Input and High Output resistance.

Trans-Resistance amplifier requires High Input and Low output resistance.

Therefore, the correct answer is "None of these "

3 0

3 years ago