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3 years ago

IF IT REQUIRES A STEADY FORCE

Engineering

1 answer:

ELEN [110]3 years ago

7 0

Answer:

i believe it is 1625 newtons

Explanation:

I could be wrong but im assuming that it is 325 newtons per meter if not then the answer could be completely different

mark brainliest if you could

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can you translate this me gusta el queso :sorry i would have put 300 points buut i used them all for my last question

Irina-Kira [14]

Translate in Spanish: lo siento, hubiera puesto 300 puntos pero los usé todos para mi última pregunta

If you meant a different language lmk

4 0

3 years ago

Consider a cylindrical nickel wire 1.8 mm in diameter and 2.6 × 104 mm long. Calculate its elongation when a load of 290 N is ap

telo118 [61]

Answer:

e = 3.97*10^-4

Explanation:

1.8 mm = 0.0018 m

2.6*10^4 mm = 26 m

Elongation is The ratio between the stretched length and the original length.

e = L/L0

This is calculated with Hooke's law:

e = σ/E

Where

σ: normal stress

E: elastic constant

σ = P/A

Where

P: normal load

A: cross section

A = π/4 * d^2

Therefore:

e = P / (A * E)

e = 4 * P / (π * d^2 * E)

e = 4 * 290 / (π * 0.0018^2 * 207*10^9) = 3.97*10^-4

8 0

3 years ago

Consider a single crystal of some hypothetical metal that has the BCC crystal structure and is oriented such that a tensile stre

velikii [3]

Complete Question

Consider a single crystal of some hypothetical metal that has the BCC crystal structure and is oriented such that a tensile stress is applied along a [121] direction. If slip occurs on a (101) plane and in a [111] direction, compute the stress at which the crystal yields if its critical resolved shear stress is 2.9 MPa.

Answer:

The stress is $\sigma = 10. 655 MPa$

Explanation:

From the question we are told that

The critical yield resolved shear stress is $\sigma = 2.9Mpa$

First we obtain the angle $\lambda$ between the slip direction [121] and [111]

$\lambda = cos^{-1} [\frac{(u_1 u_2 + v_1 v_2 + w_1 w_2}{\sqrt{u_1^2 + v_1 ^2+ w_1^2})\sqrt{( u_2^2 + v_2^2 + w_2 ^2)} } ]$

Where $u_1 ,u_2 ,v_1 , v_2 , w_1 , w_2$ are the directional indices

$\lambda = cos ^-[ \frac{(1) (-1) + (2) (1) + (1) (1)}{\sqrt{((1)^2 +(2)^2 + (1)^2)}\sqrt{((-1)^2 + (1)^2 + (1)^2 ) } } ]$

$= cos^{-1} [\frac{2}{\sqrt{6} \sqrt{3} } ]$

$= 61.87^0$

Next is to obtain the angle $\O$ between the direction [121] and [101]

$\O = cos^{-1} [\frac{(u_1 u_3 + v_1 v_3 + w_1 w_3}{\sqrt{u_1^2 + v_1 ^2+ w_1^2})\sqrt{( u_3^2 + v_3^2 + w_3 ^2)} } ]$

Substituting 1 for $u_1$ , 2 for $v_1$ , 1 for $w_1$ , 1 for $u_2$ , 0 for $v_2$ , and 1 for $w_2$

$\O = cos^{-1} [\frac{1* 1 + 2*0 + 1*1 }{\sqrt{1^2 + 2^2 + 1^2 } \sqrt{(1^2 + 0^2 + 1^2 )} } ]$

$\O = cos^{-1} [\frac{2}{\sqrt{6} \sqrt{2} } ]$

$= 54.74 ^o$

The stress is mathematically represented as

$\sigma = \frac{\tau_c}{cos \O cos \lambda }$

$= \frac{2.9}{cos 54.74^o cos 61.87^o}$

$= \frac{2.9}{0.2722}$

$\sigma = 10. 655 MPa$

5 0

3 years ago

What is the vorticity?

katovenus [111]

Answer:

a field that describes the local spinning motion of a continuum near some point

Explanation:

7 0

3 years ago

6. What symptom will be exhibited on an engine equipped with a pneumatic governor system if the cooling fins

anyanavicka [17]

<h2>Symptom of Pneumatic Governor System</h2>

Explanation:

Engine speed will rise is right answer

Pneumatic Governor system that utilizations power from moving air delivered by pivoting flywheel blades to detect engine speed
Electronic Governor System Uses a limited point torque engine in place of the governor spring and -speed-sensing device utilized in a mechanical governor system
A governor is a system that is utilized to keep up the mean speed of a engine, inside specific cutoff points, under fluctuating burden conditions
It does this by managing and controlling the measure of fuel provided to the motor
Governors are likewise fitted in assistant diesel motors or generators, and alternators on the ship

8 0

3 years ago