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Anna [14]
3 years ago
8

Technician A says that a fully charged battery is less likely to freeze than a discharged battery. Technician B says that the st

ate of charge has no impact on freezing. Who is correct
Engineering
1 answer:
zheka24 [161]3 years ago
8 0
Answer : Technician B is correct
You might be interested in
Which option identifies why Ethan’s skills are valuable to his team in the following scenario?
larisa [96]

Answer:

Explanation:

The options are:

- In an isometric drawing, multiple angles and axes can be shown in one sketch.

- There is no room for detail in an isometric drawing, so the detail is shown in the orthographic projection.

- Only one sketch will be needed since all other previous designs will no longer be necessary.

- Computer programs will not be necessary to create the exact dimensions of the design.

Orthographic projections are in either the First or Third Angles but the angles are fixed and do not provide perspective view.  Isometric drawings are perspective views from different angles.

So Ethan's skill is valuable because "In an isometric drawing, multiple angles and axes can be shown in one sketch."

4 0
3 years ago
Who was the American founder and leader of the Shakers in the 1770’s who advocated equality, individual responsibility, and peac
DaniilM [7]

Answer: Ann Lee (1736-1784)

Explanation:

6 0
3 years ago
Read 2 more answers
Air is compressed isothermally from 13 psia and 55°F to 80 psia in a reversible steady-flow device. Calculate the work required,
solong [7]

Answer:64.10 Btu/lbm

Explanation:

Work done in an isothermally compressed steady flow device is expressed as

Work done = P₁V₁ In { P₁/ P₂}

Work done=RT In { P₁/ P₂}

where P₁=13 psia

          P₂= 80 psia

Temperature =°F Temperature is convert to  °R

T(°R) = T(°F) + 459.67

T(°R) = 55°F+ 459.67

=514.67T(°R)

According to the properties of molar gas, gas constant and critical properties table, R  which s the gas constant of air is given as 0.06855 Btu/lbm

Work = RT In { P₁/ P₂}

0.06855 x 514.67 In { 13/ 80}

=0.06855 x 514.67 In {0.1625}

= 0.06855 x 514.67  x -1.817

=- 64.10Btu/lbm

The required work therefore for this  isothermal compression is 64.10 Btu/lbm

8 0
3 years ago
A square loop of wire surrounds a solenoid. The side of the square is 0.1 m, while the radius of the solenoid is 0.025 m. The sq
Semmy [17]

Answer:

I=9.6×e^{-8}  A

Explanation:

The magnetic field inside the solenoid.

B=I*500*muy0/0.3=2.1×e ^-3×I.

so the total flux go through the square loop.

B×π×r^2=I×2.1×e^-3π×0.025^2

=4.11×e^-6×I

we have that

(flux)'= -U

so differentiating flux we get

so the inducted emf in the loop.

U=4.11×e^{-6}×dI/dt=4.11×e^-6×0.7=2.9×e^-6 (V)

so, I=2.9×e^{-6}÷30

I=9.6×e^{-8}  A

6 0
3 years ago
What are the characteristic features of stress corrosion cracks?
Oduvanchick [21]

Answer and Explanation:

The crack formation growth that takes place in an environment corrosive.

Stress corrosion cracks can be defined as the spontaneous failures of the metal alloy as a result of the combined action of corrosion and high tensile stress.

Some of the characteristic features of stress corrosion cracks are:

  • These occur at high temperatures.
  • Occurrence of failures in metals mechanically.
  • Occurrence of sudden and unexpected failures under tensile stress.
  • The rate of work hardening of the metal alloy is high.
  • Time
  • An environment that is specific for stress corrosion cracking.
5 0
3 years ago
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