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Zina [86]
3 years ago
14

A town is designing a rectangular, 4m deep settling tank for treating surface water intake. The tank will have a flow velocity o

f 5 cm/s. The untreated water has particles with the following properties: d=0.025 mm and density of 2,650 kg m-3 The settler is placed following a coagulation-flocculation step which is able to do one of the following: a) Triple the diameter of the particles but have no impact on the particle density. b) Triple the density of the particles but have no impact on their diameter. 1. Which of the options would you select (a or b)? (Please explain your selection in the next question) 2. According to your selection, calculate the length of the settler (in m) required to remove the particles assuming they reach terminal velocity.
Engineering
1 answer:
Oksana_A [137]3 years ago
7 0

Answer:

333335790089

Explanation:

blh

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The files provided in the code editor to the right contain syntax and/or logic errors. In each case, determine and fix the probl
Yanka [14]

Question Continuation

public class DebugOne3{

public static void main(String args){

System.out.print1n("Over the river");

System.out.pr1ntln("and through the woods");

system.out.println("to Grandmother's house we go");

}

}

Answer:

Line 2: Invalid Syntax for the main method. The main method takes the form

public static void main (String [] args) { }

or

public static void main (String args []) { }

Line 3: The syntax to print is wrong.

To print on a new line, make use of System.out.println(".."); not System.out.print1n();

Line 4:

To print on a new line, make use of System.out.println(".."); not System.out.pr1ntln();

Line 5:

The case of "system" is wrong.

The correct case is sentence case, "System.out.println" without the quotes

The correct program goes, this:

public class DebugOne3{

public static void main(String [] args){

System.out.println("Over the river");

System.out.println("and through the woods");

System.out.println("to Grandmother's house we go");

}

}

Explanation:

3 0
3 years ago
Elizabeth has been asked to design a pool umbrella that can withstand wind speeds of up to 30 miles per hour. Now that she under
zlopas [31]

Answer:

The correct option is;

D. She will need to research the problem even more

Explanation:

In other to properly design the pool umbrella that will be reliable and meet the needs of the particular customer, she will need to carry out a basic research about the environment where the pool umbrella is to be used, the presence of other factors that can impact on an idea for the pool umbrella.

She can then proceed to create a concept about the proposed pool umbrella, which is in the form of a paper concept

She will then proceed to carry out a more detailed study based on the paper concept that will consist of concept technology and application as well as functionality.

7 0
4 years ago
Read 2 more answers
Which welding processes normally use a constant current power source? (Select all that apply) PLEASE HELP​
Furkat [3]

Answer:

Explanation:

GTAW AND GMAW

5 0
3 years ago
2.) A fluid moves in a steady manner between two sections in a flow
Talja [164]

Answer:

250\ \text{lbm/min}

625\ \text{ft/min}

Explanation:

A_1 = Area of section 1 = 10\ \text{ft}^2

V_1 = Velocity of water at section 1 = 100 ft/min

v_1 = Specific volume at section 1 = 4\ \text{ft}^3/\text{lbm}

\rho = Density of fluid = 0.2\ \text{lb/ft}^3

A_2 = Area of section 2 = 2\ \text{ft}^2

Mass flow rate is given by

m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}

The mass flow rate through the pipe is 250\ \text{lbm/min}

As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}

The speed at section 2 is 625\ \text{ft/min}.

3 0
3 years ago
What is referred to as "Pyroelectric" materials?
aliina [53]

Answer and Explanation:

Pyroelectric material

Pyroelectric materials have special property of generating potential difference (although it is very less ) when these material are treated with heat or when celled down.

The potential difference generated is for very less time

The generation of potential difference is due to change in position of atoms after heating or cooling.

5 0
3 years ago
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