Answer:
b)Poly crystalline and amorphous materials with small diameter
Explanation:
Fibers have high length to diameter ratio and also have high strength.Generally length of fibers is very high and diameter is very low as compare to length.
Mostly fibers is used to transfer data from one place to another place with help of fiber optical cables.Fiber optic cables is used in telecommunication.In these cables data covert in to the electric single and reach at define location and after data is decode and covert from electric single in to original data.
Fibers poly crystalline and amorphous materials with small diameter.
Answer:
The option that is best described as a way engineers can test and investigate how things should be under certain circumstances is;
Explanation:
Modeling is a tool an engineer can use for the physical representation of a system that will facilitate the definition, testing and analysis, communication, data generation, data verification and data validation of given concepts
Models also aid in setting specifications, supporting designs, and verification of a given system
Therefore, with modeling engineers can investigate the behavior of systems under given environmental conditions.
Answer:
a) benzene = 910 days
b) toluene = 1612.67 days
Explanation:
Given:
Kd = 1.8 L/kg (benzene)
Kd = 3.3 L/kg (toluene)
psolid = solids density = 2.6 kg/L
K = 2.9x10⁻⁵m/s
pores = n = 0.37
water table = 0.4 m
ground water = 15 m
u = K/n = (2.9x10⁻⁵ * (0.4/15)) / 0.37 = 2.09x10⁻⁶m/s
a) For benzene:
![R=1+\frac{\rho * K_{d} }{n}, \rho = 2.6\\ R=1+\frac{2.6*1.8}{0.37} =13.65](https://tex.z-dn.net/?f=R%3D1%2B%5Cfrac%7B%5Crho%20%2A%20K_%7Bd%7D%20%20%7D%7Bn%7D%2C%20%5Crho%20%3D%202.6%5C%5C%20R%3D1%2B%5Cfrac%7B2.6%2A1.8%7D%7B0.37%7D%20%3D13.65)
The time will take will be:
![t=\frac{xR}{a} , x=12,a=0.18\\t=\frac{12*13.65}{0.18} =910days](https://tex.z-dn.net/?f=t%3D%5Cfrac%7BxR%7D%7Ba%7D%20%2C%20x%3D12%2Ca%3D0.18%5C%5Ct%3D%5Cfrac%7B12%2A13.65%7D%7B0.18%7D%20%3D910days)
b) For toluene:
![R=1+\frac{2.6*3.3 }{0.37} = 24.19](https://tex.z-dn.net/?f=R%3D1%2B%5Cfrac%7B2.6%2A3.3%20%20%7D%7B0.37%7D%20%3D%2024.19)
![t=\frac{12*24.19}{0.18} =1612.67days](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B12%2A24.19%7D%7B0.18%7D%20%3D1612.67days)
Since the armature is wave wound, the magnetic flux per pole is 0.0274 Weber.
<u>Given the following data:</u>
- Number of armature conductors = 144 slots
- Number of poles = 4 poles
- Number of parallel paths = 2
To find the magnetic flux per pole:
Mathematically, the emf generated by a DC generator is given by the formula;
× ![\frac{P}{A}](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7BA%7D)
<u>Where:</u>
- E is the electromotive force in the DC generator.
- Z is the total number of armature conductors.
- N is the speed or armature rotation in r.p.m.
- P is the number of poles.
- A is the number of parallel paths in armature.
First of all, we would determine the total number of armature conductors:
×
× ![3](https://tex.z-dn.net/?f=3)
Z = 864
Substituting the given parameters into the formula, we have;
× ![\frac{4}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B2%7D)
× ![2](https://tex.z-dn.net/?f=2)
<em>Magnetic flux </em><em>=</em><em> 0.0274 Weber.</em>
Therefore, the magnetic flux per pole is 0.0274 Weber.
Read more: brainly.com/question/15449812?referrer=searchResults