Answer:
<u>the thickness required would be 12 inch HMA and granular base layer of 6 inches</u>
Explanation:
structural number = 4.5
stone base course material coefficient = 0.13
hma material layer coefficient = 0.40
drainage coefficient = 0.90
we will use layered analysis procedure to get thickness
D1 >= sN1/a1
when we cross multiply,
sN1 = a1D1 >=sN1
D2 >= -sN2-sN1/a2m2
sN2* + sN1* >= sN2
D3 >= sN3-(sN1*+sN2*)/a2m2
where a1,a2,a3 = layer coefficient
d1 d2 d3 = actual thickness
m2,m3 = coefficient of base
a1 = 0.4
a1 = 0.13
sN = 4.5
m2 = 0.9
D1 >= sN1/a1 = 4.5/0.4
= 11.25
thickness of surface = 12 inches
a1D1 = 0.4x12 = 4.8
we have value of sN2 = 5.5
(5.5 -4.8)/(0.13*0.9)
= 0.7/0.117
= 5.9829 inches
approximately 6 inches
so the pavement will have 12inch HMA surface and 6 inches granular base layer.
Answer:
The mass of car in slug =108.5 slug.
The mass of car in kilogram =1575 Kg.
Explanation:
Given that
Mass of car = 3500 lbs
We know that
1 lbs =0.031 slug
So
3500 lbs = 0.031 x 3500 slug
So the mass of car in slug =108.5 slug.
We know that
1 lbs =0.45 kilograms
so
3500 lbs = 3500 x 0.45 Kg
So the mass of car in kilogram =1575 Kg.
Answer:
the equivalent resistance of the circuit decreases and the total current of the circuit increases.
Explanation:
hope this helps