Answer: I think the right answer is c
<span>Consider two solutions: solution X has a pH of 4; solution Y has a pH of 7. From this information, we can reasonably conclude that </span>the concentration of hydrogen ions (H⁺) or hydronium ions (H₃O⁺) in solution X is thousand times as great as the concentration of hydrogen ions or hydronium ions in solution Y.
Solution X: c(H⁺) = 10∧-pH = 10⁻⁴ mol/L = 0,0001 mol/L.
Solution Y: c(H⁺) = 10⁻⁷ mol/L = 0,0000001 mol/L.
0,0001 mol/L / 0,0000001 mol/L = 1000.
The answer is caso4 and ca(C2H3O2)2
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Answer:
60.88%
Explanation:
The <em>formula for cerium carbonate</em> is Ce₂(CO₃)₃.
Let's <u>assume we have 1 mol of cerium carbonate</u>. The total mass would be equal to the molar mass of Ce₂(CO₃)₃, 460.25 g/mol.
Out of those 460.25 g, the mass <u>corresponding to cerium would be</u>:
- 2 * Molar mass of Ce = 2 * 140.11 g/mol = 280.22 g
Now we can <u>calculate the percentage by mass of cerium</u>:
- % mass = 280.22 / 460.25 * 100% = 60.88%
