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Scorpion4ik [409]
3 years ago
10

A spherical snowball melts at a rate proportional to its surface area. (a) write a differential equation for its volume, v. (use

k for the constant of proportionality.) dv dt = correct: your answer is correct. (b) if the initial volume is s, solve the differential equation.
Physics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

Explanation:

The rate of change in volume is proportional to the surface area:

dV/dt = kA

Integrating:

V = kAt + C

At t=0, V = s, so:

s = kA(0) + C

C = s

Therefore:

V = kAt + s

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block of mass 5kgriding on a horizontal frictionlessxy-plane surface is subjected tothree applied forces:→F1= 12√2N[ 45◦]→F2= (8
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Answer:

(i) See attached image for the drawing

(ii) net force given in component form: (20, 20)N with magnitude: \sqrt{800} \,\,\,N

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y-component of F1 is    F1_y=12\,\sqrt{2} \frac{\sqrt{2} }{2} =12\,\,N

As far as force F2, it is given already in x and y components, then:

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The additions of all these component by component, gives the resultant force (R) acting on the 5 kg mass:

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y-component of R = 12 + 14 - 6 = 20 N

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x-component of acceleration: 20 N / 5 kg = 4\,\,\,m/s^2

y-component of acceleration: 20 N / 5 kg = 4\,\,\,m/s^2

Now we can calculate the components of the velocity of this mass after 2 seconds of being accelerated by this force, using the formula of acceleration times time:

x-component of the velocity is:     v_x=4\,*\,2=8\,m/s

y-component of the velocity is:     v_y=4\,*\,2=8\,m/s

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