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katrin [286]
4 years ago
11

masses of 3kg on a smooth horizontal table.It is connected by a light string passing at the edge of the table to another mass of

2kg hanging vertically.When to the system is released from rest with what acceleration do the mass move​
Physics
1 answer:
allochka39001 [22]4 years ago
7 0

Answer:

aaawwwwwwwsssaaaasasss

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Give a short introduction to the Cottage and small industry development committee​
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Answer:

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Home Business Cottage and Small Industries Development Committee to organize National Industrial Goods and...

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Cottage and Small Industries Development Committee to organize National Industrial Goods and Technology Expo

By Glocal Khabar - 2368 0

National Industrial Goods and Technology Expo- Glocal Khabar

Kathmandu, February 19, 2018: Cottage and Small Industries Development Committee is set to organize the twenty-ninth edition of National Industrial Goods and Technology Expo from March 23, 2018 at Bhrikutimandap, Kathmandu.

The motto of the five-day event is ‘Let’s use home-made products, move ahead towards prosperity.’ The committee has shared that handicrafts, wool and bamboo products, goods made from handmade papers, different types of pickles and Palpali Dhaka would be put on display in the expo.

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3 years ago
When a force is acting at axis of rotation,why torque is zero?
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Explanation:

see, torque=force × perpendicular distance

...that perpendicular distance is between axis of rotation and the point where force acts... so in above's case perpendicular distance is zero... so the torque is zero!

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3 years ago
On a summer afternoon, the sand on the beach can get very hot. When you step on the sand in bare feet, you can burn yourself.
8_murik_8 [283]
<span>Heat from the Sun is transferred to the sand without direct contact. This heat is then transferred to your feet by direct contact.</span>
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3 years ago
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Robert has just bought a new model rocket, and is trying to measure its flight characteristics. The rocket engine package claims
777dan777 [17]

Answer:

The work done by the drag force is given by 29.96 J

Explanation:

Given :

Thrust force F = 12.3 N

Displacement d = 10.2 m

Mass of rocket m = 0.663 Kg

From work energy theorem,

  W = \Delta K

 W_{t} - Wd - W_{g} = KE

Where W_{t} = thrust work W_{g} = gravitational work

KE = 12.3 \times 10.2 -Wd - 0.663 \times 9.8 \times 10.2

KE = 59.2 -Wd

After cutoff kinetic energy is converted into potential energy,

KE = Wd' + mg\Delta h

Put value of KE

59.2 -Wd = Wd' + 0.663 \times 9.8 \times 4.5

Work done by drag force is given by,

Wd'+Wd =  59.2 -29.23

                 = 29.96 J

Therefore, the work done by the drag force is given by 29.96 J

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3 years ago
A device for exercising the upper leg muscle is shown above, together with a schematic representation of an equivalent lever sys
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