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alexandr1967 [171]
3 years ago
6

Shelby is seven times as old as Bonnie. In 5 years the sum of Bonnie and Shelby's ages is 98 find Bonnie's present age.

Mathematics
1 answer:
AlexFokin [52]3 years ago
5 0

Answer:

The answer is 14

Step-by-step explanation:

Step 1 Write out an expression

So since Shelby is 7 times Bonnie, Bonnie is x years old that time. So the expression is S=7x

Step 2 Plug in

Now Shelby is 98 so all u have to do is now plug in what you have in the expression.

98=7x

Step 3 solve

98=7x

divide 7 on both sides and you get:

14=x

so Bonnie is currently 14

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Bridget went fishing with her dad. Bridget Bridget caught the first fish of the day, another was 2 more than 3 times the weight
Arturiano [62]

Answer:

Bridget's first fish =f = 5 ounces

Bridget's dad first fish weighs 17 ounces

Step-by-step explanation:

Solution:

Bridget's fishes:

f ounces

2f ounces

3f+2 ounces

1/2f ounces

3/5f ounces

Total= f +2f + (3f+2) + 1/2f +3/5f

=3f + 3f + 2 + 5f+6f/10

=6f + 2 + 11f/10

=60f+11f/10 +2

=71/10f +2

Bridget's dad fishes

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2f+4

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Total =(3f+2) + (2f+4) + 4/5f +1/2f

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Collect like terms

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=3(5)+2

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