<h3>Answer:</h3>
The reactivity of an alkali metal depends on the metals ability to <u>loose an electron</u>.
<h3>Explanation:</h3>
Alkali metals are elements present in first group of the periodic table. Following are the metals from top to bottom;
Lithium
Sodium
Potassium
Rubidium
Cesium
Francium
These s-block elements are considered the most reactive metals in the periodic table because they have only one electron in their valence shell and readily loose that electron to form an ionic bond with non metal. The general electronic configuration of these metals is as follow,
nS¹
Also, the reactivity of these metals increases from top to bottom in the group as the ionization energy decreases due to increase in shielding effect respectively.
We are given that the concentration of the KCl is 2 meq /
mL. Assuming that the ampule also has exactly this concentration, therefore:
amount of KCl in ampule = (2 meq / mL) * (20 mL)
amount of KCl in ampule = 40 meq
This amount of KCl is now inside a solution of 1 Liter (also
equivalent to 1000 mL), therefore the new concentration in the resulting
solution is:
new concentration = 40 meq / 1000 mL
new concentration = 0.04 meq / mL
Since 0.04 in decimal is 4% in percentage, therefore the
strength of the resulting solution is 4% KCl.
