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Ahat [919]
3 years ago
15

An aqueous solution of hydrobromic acid is standardized by titration with a 0.164 M solution of calcium hydroxide. If 14.9 mL of

base are required to neutralize 26.9 mL of the acid, what is the molarity of the hydrobromic acid solution
Chemistry
1 answer:
Arada [10]3 years ago
6 0

Answer:

The molarity of hydrobromic acid is 0.182 M

Explanation:

Step 1: Data given

Molarity of Calcium hydroxide = 0.164 M

Volume of calcium hydroxide = 14.9 mL = 0.0149 L

Volume  of HBr = 26.9 mL = 0.0269 L

Step 2: The balanced equation

Ca(OH)2 + 2HBr →CaBr2 + 2H2O

Step 3: Calculate molarity of HBr

b*Ca*Va = a*Cb*Vb

⇒b = the coefficient of HBr = 2

⇒Ca = the molarity of Ca(OH)2 = 0.164 M

⇒Va = the volume of ca(OH)2 = 0.0149 L

⇒a= the coefficient of Ca(OH)2 = 1

⇒Cb = the molarity of HBr = TO BE DETERMINED

⇒Vb = the volume of HBr = 0.0269 L

2*0.164 * 0.0149 = 1*Cb*0.0269

Cb = 0.182 M

The molarity of hydrobromic acid is 0.182 M

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Alright sorry you're getting the answer hours later, but i can help with this.
so you're looking for specific heat, the equation for it is <span>macaΔTa = - mbcbΔTb with object a and object b. that's mass of a times specific heat of a times final minus initial temperature of a equals -(mass of b times specific heat of b times final minus initial temperature of b)
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6 0
3 years ago
What is the molariity of a 50.0 mL aqueous solution containing 10.0 grams of hydrogen peroxide, H2O2?
daser333 [38]

Answer:

6 mol/L

Explanation:

You should know or have the equation to solve for Molarity which is;

M = n/v          (M: Molarity) (n: moles of solute) (v: Liters of solute)

You can start off differently but I would start by converting the mL to L. This is your "v" value.

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Now, you have to convert grams to moles in order to solve for molarity (M).

1.) On the periodic table find the molecular weights of H and O.

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2.) Multiply them and then add them together to have their combined molecular weights. (You have to multiply by 2 because of their equation; H2O2).

2(1.01) + 2(16.00)= 34.02 g/mol

3.) Now, you're going to use the "picket fence method" or whichever your teacher taught you to convert from grams to moles. This will be your "n" value. (I cannot show it on here without it looking weird, so my sincere apologies.)

10.0 g/ 34.02 g = <em>0.2939 mol</em>

<em />

4.)You are now going to plug in your answers into the equation for Molarity.

M= 0.2939 mol / 0.05 L = <em>5.878 mol/L</em>

5.) I am sure your professor might be a stickler so for sig figs sake when you multiply or divide use the smallest amount of sig figs you see which is 1. Round 5.878 to 6 mol/L

Sorry this explanation is very long let me know if you need a better more written out explanation.

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Umnica [9.8K]
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mel-nik [20]

Answer:

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Explanation:

Hello,

In this case, as the Gibbs free energy for a reaction is defined in terms of the change in the enthalpy and entropy as shown below:

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Thus, as the reaction becomes spontaneous (ΔG°<0) at temperatures above 1100K (high temperatures), it necessary that c. ΔH° is positive and ΔS° is positive as the entropy will drive the spontaneousness as it becomes smaller than TΔS°.

Best regards.

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