Answer:
The molarity of hydrobromic acid is 0.182 M
Explanation:
Step 1: Data given
Molarity of Calcium hydroxide = 0.164 M
Volume of calcium hydroxide = 14.9 mL = 0.0149 L
Volume of HBr = 26.9 mL = 0.0269 L
Step 2: The balanced equation
Ca(OH)2 + 2HBr →CaBr2 + 2H2O
Step 3: Calculate molarity of HBr
b*Ca*Va = a*Cb*Vb
⇒b = the coefficient of HBr = 2
⇒Ca = the molarity of Ca(OH)2 = 0.164 M
⇒Va = the volume of ca(OH)2 = 0.0149 L
⇒a= the coefficient of Ca(OH)2 = 1
⇒Cb = the molarity of HBr = TO BE DETERMINED
⇒Vb = the volume of HBr = 0.0269 L
2*0.164 * 0.0149 = 1*Cb*0.0269
Cb = 0.182 M
The molarity of hydrobromic acid is 0.182 M
