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goldenfox [79]
3 years ago
15

A compound C6H12 reacts instantly

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer and Explanation:

Since the compound C6H12 reacts with Br2 to give a dibromide, that means it contains one double bond and also since it gives an aldehyde C2H4O as one of the products, the ozonolysis implies that one end of the double bond is =CHCH3 and because the other product is C4H8O, the original compound has this structure in the attachment below. The original compound is 2-hexene.

(The structure of C6H12Br2 is also in the attachment below)

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The pathway by which carbon is transferred from living organisms to the atmosphere is called:
Phoenix [80]

Answer:

cellular respiration

Explanation:

All exergonic processes produced in the cell, through which substances oxidize and chemical energy is released, are grouped under the name of cellular respiration, but to break down an organic molecule the cells employ, mainly dehydrogenations that can be carried carried out in the presence or absence of atmospheric O2 oxygen. There are therefore two types of breathing: aerobic respiration and anaerobic respiration. The latter also called fermentation.

Aerobic respiration  (oxidative phosphorylation)

- Use molecular O2.

- It degrades glucose to CO2 and H2O

- Exergonic

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3 0
3 years ago
Determine Z and V for steam at 250°C and 1800 kPa by the following: (a) The truncated virial equation [Eq. (3.38)] with the foll
makvit [3.9K]

Answer:

Explanation:

Given that:

the temperature T_1 = 250 °C= ( 250+ 273.15 ) K = 523.15 K

Pressure = 1800 kPa

a)

The truncated viral equation is expressed as:

\frac{PV}{RT} = 1 + \frac{B}{V} + \frac{C}{V^2}

where; B = - 152.5 \ cm^3 /mol   C = -5800 cm^6/mol^2

R = 8.314 × 10³ cm³ kPa. K⁻¹.mol⁻¹

Plugging all our values; we have

\frac{1800*V}{8.314*10^3*523.15} = 1+ \frac{-152.5}{V} + \frac{-5800}{V^2}

4.138*10^{-4}  \ V= 1+ \frac{-152.5}{V} + \frac{-5800}{V^2}

Multiplying through with V² ; we have

4.138*10^4  \ V ^3 = V^2 - 152.5 V - 5800 = 0

4.138*10^4  \ V ^3 - V^2 + 152.5 V + 5800 = 0

V = 2250.06  cm³ mol⁻¹

Z = \frac{PV}{RT}

Z = \frac{1800*2250.06}{8.314*10^3*523.15}

Z = 0.931

b) The truncated virial equation [Eq. (3.36)], with a value of B from the generalized Pitzer correlation [Eqs. (3.58)–(3.62)].

The generalized Pitzer correlation is :

T_c = 647.1 \ K \\ \\ P_c = 22055 \  kPa  \\ \\ \omega = 0.345

T__{\gamma}} = \frac{T}{T_c}

T__{\gamma}} = \frac{523.15}{647.1}

T__{\gamma}} = 0.808

P__{\gamma}} = \frac{P}{P_c}

P__{\gamma}} = \frac{1800}{22055}

P__{\gamma}} = 0.0816

B_o = 0.083 - \frac{0.422}{T__{\gamma}}^{1.6}}

B_o = 0.083 - \frac{0.422}{0.808^{1.6}}

B_o = 0.51

B_1 = 0.139 - \frac{0.172}{T__{\gamma}}^{ \ 4.2}}

B_1 = -0.282

The compressibility is calculated as:

Z = 1+ (B_o + \omega B_1 ) \frac{P__{\gamma}}{T__{\gamma}}

Z = 1+ (-0.51 +(0.345* - 0.282) ) \frac{0.0816}{0.808}

Z = 0.9386

V= \frac{ZRT}{P}

V= \frac{0.9386*8.314*10^3*523.15}{1800}

V = 2268.01 cm³ mol⁻¹

c) From the steam tables (App. E).

At T_1 = 523.15 \  K \ and  \ P = 1800 \ k Pa

V = 0.1249 m³/ kg

M (molecular weight) = 18.015 gm/mol

V  =  0.1249 × 10³ × 18.015

V = 2250.07 cm³/mol⁻¹

R = 729.77 J/kg.K

Z = \frac{PV}{RT}

Z = \frac{1800*10^3 *0.1249}{729.77*523.15}

Z = 0.588

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3 years ago
A student placed a stack of rocks on a ramp. She added clumps of soil rooted with live grass. Using a garden hose, she then appl
Sliva [168]
<span>Answer D. Spray from the hose suggests water in liquid state falling into the soil. The process of elimination: A glacier can be related to water in frozen but in static state. B Fast winds has the element of movement of air, not water. C. A hail storm, movement of water in frozen state. D. Heavy rains looks to be better choice compares to the others.</span>
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Read 2 more answers
Wet snow is best for snow man building<br>​
fredd [130]

Answer:

<h2>Hope my answer helps</h2>

Explanation:

<h2>Moist to wet snow is the ideal moisture content needed to build the best snowman. If the snow is too dry, it is comparable to loose powder and in turn, the snow won't stick together. On the other hand, if the snow has too much moisture and is slushy, it can't form into a solid.</h2>
4 0
3 years ago
You are given a cube of lead that is 1.000 cm on each side. The density of lead is 11.35. How many atoms of lead are in the samp
aliya0001 [1]

<u>11.35 g</u><u> </u><u>atoms </u><u>of lead are in the sample.</u>

What does density mean?

  • The density of an area refers to the quantity of things—which may include people, animals, plants, or objects—there are in it.
  • Divide the number of objects by the area's measurement to determine density.
  • A country's population density is calculated by dividing its total population by its area, expressed in square kilometers or miles.

We can calculate the volume of the cube by cubing the side of the cube.

Volume of cube = ( 1.000 cm)³

                           = 1.000 cm³

We can now determine the amount of lead in the cube by multiplying by the density. Because we know we have a 1.000 cubic centimeter and that lead has a density of 11.35 grams per cubic centimeter, we have 11.35 grams of lead.

           =  ( 1.000 cm³) ( 11.35 \frac{g}{cm^{3} } )

         = 11.35 g

Learn more about density

brainly.com/question/15164682

#SPJ4

3 0
2 years ago
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