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3 years ago

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What si unit measures speed ?

1 answer:

dlinn [17]3 years ago

4 0

Hmm doesnt soujd familiar

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The fundamental resolution of an optical instrument is set by __________.

inysia [295]

Answer:C . The wave nature of light.

Explanation: The wave nature of light has been described in the refraction and diffraction of light when it comes in contact with a prism.

Wave nature of light has been described through this equation C= velocity( measured in meters per second square), Wavelength (lambda) which is the distance between successive antinodes or nodes,it is measured in meters. and Frequency is the number of times light waves pass through a point in one second, usually measured in Hertz(Hz)

Below is a

Thin-lens equation (also works for mirrors)

1/f=1/u+1/v

Where f is the focal length, u is distance of object,v is the distance between the optical centre and the image of the object.

6 0

3 years ago

An 18 gauge copper wire (the size usually used for lamp cords), with a diameter of 1.02 mm,1.02 mm, carries a constant current o

larisa86 [58]

Answer:

J = 2.044x10⁶ A/m²

v = 1.50x10⁻⁴ m/s

Explanation:

The current density (J) of the copper wire is giving by:

$J = \frac {I}{A}$

<em>where I: electric current and A: cross-sectional area of the copper wire</em>

<u>The cross-sectional area of the copper wire can be calculated by:</u>

$A = \frac {\pi d^{2}}{4} = \frac {\pi (1.02 \cdot 10^{-3} m)^{2}}{4} = 8.17 \cdot 10^{-07} m^{2}$

<u>Substituting the calculated area in the equation (1) we have:</u>

$J = \frac {1.67 A}{8.17 \cdot 10^{-7} m^{2}} = 2.044 \cdot 10^{6} \frac {A}{m^{2}}$

Hence, the current density is 2.044x10⁶ A/m².

To find the drift speed (v), we need to use the next equation:

$v = \frac {J}{n q}$

<em>where n: the free-electron density, q: module of the charge of the electron </em>

$v = \frac {2.044 \cdot 10^{6} \frac {A}{m^{2}}}{(8.5 \cdot 10^{28} {m^{-3}}) (1.6 \cdot 10^{-19} C)}$

$v = 1.50 \cdot 10^{-04} \frac {m}{s}$

So, the drift speed is 1.50x10⁻⁴ m/s.

Have a nice day!

4 0

4 years ago

Read 2 more answers

As longitudional waves travel, particles in the medium are pushed together and then pulled apart. We call this

lawyer [7]

Compression and rarefaction.

4 0

4 years ago

Read 2 more answers

Calculate the volume of this regular solid. A cylinder labeled B at the top, 13 centimeters high with a radius of 4 centimeters.

Kryger [21]

Answer:

The volume of the cylinder is $653.71\ \text{cm}^3$

Explanation:

Given that,

The height of the cylinder is 13 cm

Radius of the cylinder is 4 cm

We need to find the volume of the cylinder. The formula that is used to find the volume of a cylinder is given by :

$V=\pi r^2 h\\\\V=\dfrac{22}{7} \times (4)^2 \times 13\\\\V=653.71\ \text{cm}^3$

So, the volume of the cylinder is $653.71\ \text{cm}^3$

4 0

3 years ago

Read 2 more answers

Please answer this as soon as possible

Alinara [238K]

I think it’s the third one, if not it’s the first.

4 0

3 years ago