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worty [1.4K]
4 years ago
14

A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with sequals17.6 millig

rams. Construct a​ 95% confidence interval for the true mean cholesterol content of all such eggs.
Mathematics
1 answer:
dedylja [7]4 years ago
6 0

Answer: 95% confidence interval would be (175.04,194.96).

Step-by-step explanation:

Since we have given that

Mean = 185 mg

Standard deviation = 17.6 mg

At 95% confidence level, z = 1.96

So, Interval would be

\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=185\pm 1.96\times \dfrac{17.6}{\sqrt{12}}\\\\=185\pm 9.958\\\\=(185-9.958,185+9.958)\\\\=(175.042,194.958)\\\\=(175.04,194.96)

Hence, 95% confidence interval would be (175.04,194.96).

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If the original quantity is 10 and the new quantity is ​14, what is the percent​ increase?
Korvikt [17]

Answer:

40% increase

Step-by-step explanation:

10 is you 100%

if it increased to 14, then that means your 100% = 10 increased +4 which is the 40%

6 0
3 years ago
In 2010, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephon
Zepler [3.9K]

<u>Answer</u>: No, we do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

Step-by-step explanation:

As per given , we have

H_0: \mu=9.4\\\\H_a:\mu\neq9.4, since H_0 is two-tailed so , the test is a two tail test.

Since population standard deviation is unknown, so we use t-test.

Critical value (two-tailed) for significance level of 0.01= t_{n-1,\alpha/2}=t_{49, 0.005}\pm2.609228

For n =50 , \overline{x}=8.6 and s= 4.8

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

t=\dfrac{8.6-9.4}{\dfrac{4.8}{\sqrt{50}}}\approx-1.18

Since test statistic value (-1.18) lies in critical interval (-2.609228, 2.609228), it means the null hypothesis is failed to reject.

We do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

4 0
3 years ago
If x = 7 and f = 4 and g = 9 and l = 24 and p = 12 and e = 9847493 then what is x ÷ fg X i ÷ p
REY [17]
0.38^• or 7/18. If the x after the g and before the i is a multiplication (btw the ^• is a repeater
3 0
3 years ago
Find the Range of the following set of data. (Round to the
loris [4]

Step-by-step explanation:

put them in least to greatest, so that would be: 0,0,1,1,1,1,2,3,3,6,8,7,8, then do the greatest minus the lowest: 8-0=8

5 0
3 years ago
An artist is constructing a piece of art in the shape of rectangle. The artist wants to use string to tightly tie each vertex of
Liula [17]

Answer:

  65.8 ft

Step-by-step explanation:

The number of strings required to tie each vertex to the other three will be ...

  (4)(3)/2 = 6

Those strings will be perimeter strings plus two diagonal strings. The lengths of the perimeter strings are given as 12 ft and 7 ft. The lengths of the diagonal strings can be found using the Pythagorean theorem.

  d² = 12² +7² = 144 +49 = 193

  d = √193 ≈ 13.892

Then the total length of all strings is ...

  L = 2(12.0 +7.0 +13.9) = 65.8 . . . . feet

The artist will need 65.8 feet of string.

4 0
3 years ago
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