Carbon monoxide is the most common type of poisoning by gases
Answer:
Time taken by space shuttle = 714.28 m/s
Explanation:
Given:
Distance cover by space shuttle = 500,000 meter
Speed of space shuttle = 700 m/s
Find:
Time taken by space shuttle
Computation:
Time taken = Distance / Speed
Time taken by space shuttle = Distance cover by space shuttle / Speed of space shuttle
Time taken by space shuttle = 500,000 / 700
Time taken by space shuttle = 714.28 m/s
Answer:
the diagram explains the process of DNA digestion and DNA ligation, which is usually used in molecular cloning techniques
Explanation:
Molecular cloning can be defined as the process used to synthesize multiple copies of a particular DNA fragment. Molecular cloning requires the insertion of a foreign DNA fragment into an appropriate vector (e.g., a plasmid) through the action of specific enzymes that serve to cut and ligate DNA fragments. DNA digestion and DNA ligation use specific restriction enzymes and DNA ligases, respectively, in order to insert the foreign DNA fragment. For this purpose, restriction enzymes that generate single-stranded overhangs are preferred to create sticky ends which bind by complementary base pairing. Subsequently, a DNA ligase enzyme joins the DNA fragments together in order to create recombinant DNA molecules. DNA Ligation is often achieved by using a specific T4 DNA ligase, while there are many restriction enzymes that generate sticky-ends (e.g., BamHI, EcoRI, BaI228I, etc).
Answer:
C. It is a male with atleast one dominant allele
Explanation:
In the given pedigree, the two normal parents of the generation I have one daughter with the attached earlobe. Since the trait is recessive, the daughter should be homozygous recessive to express the trait. The genotype of the daughter (shaded circle in generation II) is "aa". To have a daughter with "aa" genotype, both the parents should have one copy of "a" allele. So, the genotype of both parents is "Aa".
In generation II, individual A is non-shaded square. Squares represent males in a pedigree. Since its not shaded, it does not have attached earlobe. Both the parents are heterozygous dominant for attached earlobes (Aa x Aa = 1/4 AA : 1/2 Aa : 1/4 aa). The genotype of this individual may be AA or Aa.
Answer:
Juan
Explanation:
Given the information from the question. We need to find out which person will get the best resolution and the reason thereafter. Since we know that the resolution is directly proportional or relative to N (A). Based on the information provided .Juan will have the best resolution due to higher N (A). Therefore, the correct answer is Juan.
