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1 year ago

a prescriber has ordered childrens motrin 400 mg po q6h for a child who weighs 60 kg. how many mg/kg is the child receiving

Chemistry

1 answer:

DedPeter [7]1 year ago

5 0

Answer:

6.67 mg/kg per dose ( 26.67 mg/kg per day)

Explanation:

400 mg / 60 kg = 6 2/3 mg/kg per dose

per <em>DAY</em> is four times this number

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Which of the following elements has the largest ionization

Tanya [424]

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3 years ago

Which colorless and odorless gas, produced by radioactive decay of Uranium-238, is considered to be a cancer-causing agent?

DiKsa [7]

B, radon is correct. Interestingly, it often collects in basements from radioactive decay of rocks such as granite that contain uranium. Because it is an unreactive noble gas and because it is denser than air it sits in basements and must be pumped out. It collects in human lungs and is the second leading cause of lung cancer behind smoking.

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3 years ago

A reaction at -6.0 °C evolves 786. mmol of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is co

borishaifa [10]

Answer:

V of Sulfur tetrafluoride is 17.2 L

Explanation:

Given data;

T = -6°C = 267K [1° C = 273 K]

n = 786 mmol of SF4 which is 0.786 mol

P = 1 atm

from ideal gas law we have

PV = nRT

where n is mole, R is gas constant, V is volume

$V = \frac{nRT}{P}$ $V = \frac{0.786 mol \times 0.082 atmL/mol K \times* 267K}{1atm} = 17.2 L$

V of Sulfur tetrafluoride is 17.2 L

6 0

3 years ago

Consider the reaction 2CO * O2 —> 2 CO2 what is the percent yield of carbon dioxide (MW= 44g/mol) of the reaction of 10g of c

Arturiano [62]

Answer:

Y = 62.5%

Explanation:

Hello there!

In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

$m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO} *\frac{44gCO_2}{1molCO_2}\\\\ m_{CO_2}^{theoretical}=16gCO_2$

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

$Y=\frac{10g}{16g} *100\%\\\\Y=62.5\%$

Best regards!

8 0

2 years ago

How many moles of atoms are in 7.00 g of carbon 13 a b c d?

EastWind [94]

<span>7/13 moles because a mole is one gram times the molecular weight. </span>

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3 years ago