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Andreas93 [3]
4 years ago
14

Please help this is timed. What is the total number of complete waves in the graph below

Chemistry
1 answer:
Viktor [21]4 years ago
3 0

Answer:

2

Explanation:

you go from the middle line where it starts until you hit where it starts the pattern so if you took that shape it and flipped the bottom part it makes a big, complete oval

I hope this helped :))

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A balloon is filled with 35.0 L of helium in the morning when the temperature is 303 degrees kelvin. By 3:00 p.m., the temperatu
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Answer:

The new volume of the balloon is 38.5 L

Explanation:

Step 1: Data given

Volume at the start = V1 = 35.0 L

Temperature at the start = T1 = 303 Kelvin

Volume by 3pm = TO BE DETERMINED

Temperature by 3pm = 333 Kelvin

<u>Step 2: </u>Calculate the new volume

Charles' gas law says

V1/T1  = V2/T2

V 1  is the initial volume and T1 is the initial temperature

V2 is the final volume and T2 is the final temperature

35 L / 303 Kelvin = V2 / 333 Kelvin

V2 = 35L * 333 Kelvin / 303 Kelvin

V2 = 38.47L ≈ 38.5 L

The new volume of the balloon is 38.5 L

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When 100 mL of 0.200 M NaCl(aq) and 100 mL of 0.200 M AgNO3(aq), both at 21.9 °C, are mixed in a coffee cup calorimeter, the tem
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Answer:

There is 1.3 kJ heat produced(released)

Explanation:

<u>Step 1:</u> Data given

Volume of a 0.200 M Nacl solution = 100 mL = 0.1 L

Volume of a 0.200 M AgNO3 solution = 100 mL = 0.1 L

Initial temperature = 21.9 °C

Final temperature = 23.5 °C

Solid AgCl will be formed

<u>Step 2</u>: The balanced equation:

AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)

AgCl(s) + NaNO3(aq) → Na+(aq) + NO3-(aq) + AgCl(s)

<u>Step 3:</u> Define the formula

Pressure is constant.  → the heat evolved from the reaction is equivalent to the enthalpy of reaction.  

Q=m*c*ΔT

⇒ Q = the heat transfer (in joule)

⇒ m =the mass (in grams)

⇒ c= the heat capacity (J/g°C)

⇒ ΔT = Change in temperature = T2- T1

Step 4: Calculate heat

Let's vonsider the density the same as the density of water (1g/mL)

Mass = volume * density

Mass = 200 mL * 1g/mL

Mass = 200 grams

Q= m*c*ΔT

⇒ m = 200 grams

⇒ c = the heat capacity (let's consider the heat capacity of water) = 4.184 J/g°C

⇒ ΔT = 23.5 -21.9 = 1.6°C

Q = 200 * 4.184 * 1.6 = 1338 .9 J = 1.3 kJ

There is 1.3 kJ heat produced(released)

Therefore, we assumed no heat is absorbed by the calorimeter, no heat is exchanged between the  calorimeter and its surroundings, and the specific heat and mass of the solution are the same as those for  water (1g/mL and 4.184 J/g°C)

7 0
3 years ago
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