In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.
Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.
For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.
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<span>Answers are:
-4 for C in CH4, because carbon has greater electronegativity than hydrogen and he attracts shared electrons.
</span><span>+4 for C in CO2, because carbon has smaller electronegativity than oxygen.
</span><span>+1 for H in both CH4 and H2O, because hydrogen has amaller electronegativity than both carbon and oxygen.
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Answer:
The second choice, or flammability.
Explanation:
The flammability of something is how easy it is for it to burn or ignite.
Answer:
the sum is Rs 4,200
Explanation:
Given that
3 by 7 of the sum is $1,800
We need to find out the sum
So,
Here we assume the sum be x
So the following equation should be made
3 ÷ 7 × x = 1800
3x = 1800 × 7
x = (1800 × 7) ÷ 3
= Rs 4,200
Hence, the sum is Rs 4,200
The same would be considered and relevant
Solar, or <span>radiant to chemical.</span>