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3241004551 [841]
1 year ago
10

The highest energy occupied molecular orbital in the C-C bond of the C2 molecule is?

Chemistry
1 answer:
Butoxors [25]1 year ago
5 0

The highest energy occupied molecular orbital in the C-C bond of the C₂ molecule is 2pπ orbitals.

<h3>What is Molecular Orbital Theory?</h3>

According to this theory,

  • Molecular orbitals are formed by intermixing of atomic orbitals of two or more atoms having comparable energies
  • The number of molecular orbitals formed is equal to the number of atomic orbitals combined.
  • The shape of molecular orbitals formed depends on the type of atomic orbitals combined
  • Only atomic orbitals having comparable energies and the same orientation can intermix
  • Bonding M.O. is formed by the additive effect of atomic orbitals and thus, has lower energy and high stability.
  • Antibonding M.O. is formed by the subtractive effect of atomic orbitals and thus, has higher energy and low stability.
  • Bonding M.O. is represented by \sigma, \pi, \delta while Antibonding M.O. is represented by \sigma^*, \pi^*, \delta^*\\

Molecular Orbital Diagram of C₂

Learn more about Molecular Orbital Theory:

brainly.com/question/17371976

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For the reaction KClO2⟶KCl+O2 KClO2⟶KCl+O2 assign oxidation numbers to each element on each side of the equation. K in KClO2:K i
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Answer:

Explanation:

The formula of the reaction:

            KClO₂ → KCl + O₂

To assign oxidation numbers, we have to obey some rules:

  1. Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
  2. The charge on simple ions signifies their oxidation number.
  3. The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.

The oxidation number of K in KClO₂:

                                   K + (-1) + 2(-2) = 0

                                    K-5 = 0

                                    K = +5

The oxidation number of K in KCl:

                                K + (-1) = 0

                                K = +1

The oxidation number Cl in KClO₂ is -1

For Cl in KCl, the oxidation number is -1

For O in KClO₂, the oxidation number is (2 x -2) = -4

For O in O₂, the oxidation number is 0

K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.

O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.

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First, get about 20 mL of the quinine stock solution in a clean beaker to prepare 250 mL of about 2 ppm quinine in 0.05 M H2SO4.
iris [78.8K]

Answer:

Volume of acid, Va=250mL; Volume of quinine,Vb=20mL; Molarity of acid, Ma=0.05M.

Molar mass of acid= H2+S+O4= 2+32+(16X4)= 2+32+64=98g

Concentration of acid, Ca= Molar mass of acid/ Ma =98/0.05=1960g/mol

Explanation: To calculate concentration of quinine, Cb is as follow

Va*Ca=Vb*Cb

∴ Cb=Va*Ca/Vb =250*1960/20 =24500g/mol

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