Answer:
-138.9 kJ/mol
Explanation:
Step 1: Convert 235.8°C to the Kelvin scale
We will use the following expression.
K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K
Step 2: Calculate the standard enthalpy of reaction (ΔH°)
We will use the following expression.
ΔG° = ΔH° - T.ΔS°
ΔH° = ΔG° / T.ΔS°
ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K
ΔH° = -3.583 kJ (for 1 mole of balanced reaction)
Step 3: Convert -9.9°C to the Kelvin scale
K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K
Step 4: Calculate ΔG° at 263.3 K
ΔG° = ΔH° - T.ΔS°
ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K
ΔG° = -138.9 kJ/mol
Answer:
87.5198
Explanation:
(43.65 * 87.05) + (48.25 * 87.93) + (8.11 * 87.50) = 8751.98
8751.98 / 100 = 87.5198
Explanation:
Dipole moment is defined as the measurement of the separation of two opposite electrical charges.
is a bent shaped molecule with a dipole moment of 1.87.
is also a bent shaped molecule with a dipole moment of 1.10.
is a also a bent shaped molecule and has a negligible dipole moment.
has a dipole moment of 0.29.
Therefore, given molecules are arranged according to their increasing dipole moment as follows.
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True. A mole is a standard unit of measurement. It's like that riddle; "What's heavier, a pound of bricks or a pound of feathers? Neither- a pound is a pound no matter what it's made of."
1.molecular element
2.ionic compound
3.molecular compound
4. molecular compound