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Strike441 [17]
3 years ago
9

old blooded animals modulate the fatty acid composition of their membranes as a function of temperature in order to A) ensure co

nsistent membrane fluidity. B) maximize available fatty acids for metabolic use. C) adjust the membrane thickness and increase thermal insulation. D) compensate for decreasing cholesterol solubility. E) all of the above
Chemistry
1 answer:
horsena [70]3 years ago
6 0

Answer:

<em>In order to ensure consistent membrane fluidity</em>

Explanation:

<h3>Cold Blooded Animals</h3>

Cold-blooded animals rely on the temperature of the surrounding environment to maintain its internal temperature, their blood is not cold.  Their body temperature fluctuates,  based on the external temperature of the environment. If it  is 30 °F outside, their body temperature  will eventually normalize to  30 °F, as well. If it eventually rises to 120 °F, their body temperature will follow the same pattern to 120 °F.

<h3>Membrane fluidity</h3>

The cell membrane of cold-blooded animals contains cholesterol, which acts as a shield for the membrane. Membrane fluidity is enhanced by temperature, as the temperature increases membrane fluidity increases and it decreases when the temperature goes down.

<em>Most cold-blooded animals adjust their feeding habit to contain  more </em><em>unsaturated fats</em><em> from plants. This helps them to maintain their </em><em>motor coordination and membrane </em><em> fluidity during the long winter</em>

Cold-blooded animals modulate the fatty acid composition of their membrane to stabilize their membrane fluidity

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When 4.15 grams of silver nitrate is reacted with 1.11 grams of iron(III) chloride, which best represents the amount of silver c
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Answer:

The mass of silver chloride produced = 2.202 g

Explanation:

Equation of the reaction is given below

3AgNO₃(aq) + FeCl₃(aq) ----> 3AgCl(s) + Fe(NO₃)₃(aq)

molar mass of AgNO₃ = 170 g/mol

molar mass of FeCl₃ = 233.5 g/mol

molar mass of AgCl = 143.5 g/mol

3 moles of silver nitrate reacts with 1 mole of iron (iii) chloride to give 3 moles of silver nitrate

4.15 grams of AgNO₃ = 4.15/170 = 0.0244 moles of AgNO₃

1.11 grams of FeCl₃ = 1.11/233.5 = 0.0047 moles of FeCl₃

mole ratio of AgNO₃ to FeCl₃ = 0.0244/0.0047 = 5 : 1

therefore, FeCl₃ is the limiting reactant

0.0047 moles of FeCl₃ reacting will produce 0.0047 *  3 moles of AgCl = 0.0141 moles of AgCl

0.0141 moles of AgCl = 0.0141 * 143.5 g of AgCl = 2.02 g of AgCl =

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