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7nadin3 [17]
3 years ago
5

In a double-replacement reaction, there are two reactants and ____________________ product(s

Chemistry
1 answer:
bixtya [17]3 years ago
3 0

Answer:

Two

Explanation:

In a double-replacement reaction, there will be two reactants and two products.

It is called double replacement reaction because one element in reactant 1 replaces an element in reactant 2 and other element in reactant 2 replaces other element in reactant 1.

Here two replacements are taking place. Hence, this is called double replacement reaction.

A Neutralization reaction i.e an Acid - Base reaction is a good example of Double replacement reaction.

An Example is provided below for better understanding :

HNO3 + NaOH --> NaNO₃ + H₂O.

Here HNO₃ is the acid and NaOH is the base which are the reactants.

NaNO₃ and H₂O are the products.

This is a double replacement reaction because,

Hydrogen(H) in  HNO₃ replaces Sodium(Na) in NaOH, and

NO₃ in HNO₃ replaces OH in NaOH.

Here, there are 2 reactants and 2 products.

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Find the quantinum numbers n,m,l,s for the last of potassium layer pleasee help explain correctly all
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Answer:

Quantum numbers of the outermost electron in potassium:

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Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the 4s orbital (fourth s orbital.)

The quantum number n (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, n = 4 for this electron.

The quantum number l (the angular momentum quantum number) specifies the shape (s, p, d, etc.) of an electron. l = 1 for s\! orbitals (such as the one that contains this electron.

Quantum numbers n and l specify the shape of an orbital. On the other hand, the magnetic quantum number m_l specifies the orientation of these orbitals in space.

However, s orbitals are spherical. Regardless of the value of n, the only possible m_l value for electrons in s\! orbitals is m_l = 0.

The spin quantum number m_s distinguishes between the two electrons in an orbital. The two possible values of m_s \! are (+1/2) and (-1/2). Typically, the first electron in an orbital is assigned an upward (\uparrow) spin, which corresponds to m_s = (+1/2).

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