Answer: 1, magnesium & mg
2, two energy shells
Explanation:
Molar mass
C₂H₄O₂ = 60.0 g/mol
n = mass / molar mass
3.00 = mass / 60.0
m = 3.00 * 60.0
m = 180 g of <span>C₂H₄O₂
hope this helps!</span>
Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant

parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting the values in the equation

T = 4342 K
initial temperature was 4342 K
Answer: At equilibrium, the partial pressure of
is 0.0330 atm.
Explanation:
The partial pressure of
is equal to the partial pressure of
. Hence, let us assume that x quantity of
is decomposed and gives x quantity of
and x quantity of
.
Therefore, at equilibrium the species along with their partial pressures are as follows.
At equilibrium: 0.123-x x x
Now, expression for
of this reaction is as follows.
![K_{p} = \frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}\\0.0121 = \frac{x \times x}{(0.123 - x)}\\x = 0.0330](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20%5Cfrac%7B%5BPCl_%7B3%7D%5D%5BCl_%7B2%7D%5D%7D%7B%5BPCl_%7B5%7D%5D%7D%5C%5C0.0121%20%3D%20%5Cfrac%7Bx%20%5Ctimes%20x%7D%7B%280.123%20-%20x%29%7D%5C%5Cx%20%3D%200.0330)
Thus, we can conclude that at equilibrium, the partial pressure of
is 0.0330 atm.
The volume of chlorine gas measured at STP will be liberated by a current of 2.5 A flowing for a period of 1.8 hours through an aqueous solution of AgCl is 1.88 litre.
<h3>What is Faraday's law ?</h3>
According to Faraday's Law , During Electrolysis , The amount of substance liberated at the cathode or anode is directly proportional to the electricity that is passed through the cell.
The reaction taking place at anode is:
2Cl → Cl₂ +2e −
The total charge is calculated as
Q=I×t= 2.5×1.8×60×60 coulomb
Q = 16200 coulomb
The amount of chlorine liberated by passing 16200 coulomb of electric charge
= 16200/(2*96500)
= 0.084 mole
Volume of Cl₂ at STP is
1 mole at STP has 22.4 L of Gas
0.084 mole of Cl₂ at STP will be equal to 22.4 *0.084 = 1.88 litre of Cl₂
To know more about Faraday's Law
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