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12345 [234]
3 years ago
11

A woman pulls on a 6.00-kg crate, which in turn is connected to a 4.00-kg

Physics
2 answers:
djverab [1.8K]3 years ago
7 0

Answer:

B. is subject to a smaller net force but same acceleration.

Explanation:

F = m*a

So because our force applied is constant from the women pulling on the rope which means the acceleration is the same on both the 4kg create and the 6kg create. The only thing that changes here is the mass of the creates, so there is more tension force between the women and the 6kg create then there is between the 4kg create and the 6kg. It takes less force to move the 4kg create therefore the tension force is less between the two creates.

Anastasy [175]3 years ago
7 0

Answer:

Explanation:

We know that when force (F) is applied then both the crate will move together so both have same acceleration.

And from Newton's 2 nd law we have:

F= ma , where m= mass of crate and a is acceleration.

Now for crate of mass 4 kg we have:

F = ma = 4a Newton.    

For the crate of mass 6 kg we have:

F = ma = 6a Newton.    

Hence the crate having less mass is subjected with smaller net force .

Hence from the above we can conclude that the correct answer is option 3 which is : is subjected to a smaller net force and has the same acceleration.

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A wheel, starting from rest, rotates with a constant angular acceleration of 1.80 rad/s^2. During a certain 7.00 s interval, it
lora16 [44]

Answer:

a) 1.3 rad/s

b) 0.722 s

Explanation:

Given

Initial velocity, ω = 0 rad/s

Angular acceleration of the wheel, α = 1.8 rad/s²

using equations of angular motion, we have

θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²

where

θ2 - θ1 = 53.2 rad

t2 - t1 = 7s

substituting these in the equation, we have

θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²

53.2 =ω(0) * 7 + 1/2 * 1.8 * 7²

53.2 = 7.ω(0) + 1/2 * 1.8 * 49

53.2 = 7.ω(0) + 44.1

7.ω(0) = 53.2 - 44.1

ω(0) = 9.1 / 7

ω(0) = 1.3 rad/s

Using another of the equations of angular motion, we have

ω(0) = ω(i) + α*t1

1.3 = 0 + 1.8 * t1

1.3 = 1.8 * t1

t1 = 1.3/1.8

t1 = 0.722 s

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3 years ago
In an experiment to determine the s.h.c. of lead, a 0.80 kg block of lead is heated using a
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Answer:2.47

Explanation: did the math

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2 years ago
A hot air balloon rising vertically is tracked by an observer located 3 miles from the lift-off point. At a certain moment, the
yuradex [85]

Answer:

\frac{dy}{dt}=1.2\frac{mi}{min}

Explanation:

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\frac{dx}{dt}=0 since x is a constant value. Replacing:

\frac{dy}{dt}=3mi(sec^{2}\frac{\pi}{3})0.1\frac{rad}{min}\\\frac{dy}{dt}=1.2\frac{mi}{min}

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Question 4
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Answer:

one of the object is at rest after the collision

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There are two types of addiction, psychological and physical. A. True B. False
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