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12345 [234]
3 years ago
11

A woman pulls on a 6.00-kg crate, which in turn is connected to a 4.00-kg

Physics
2 answers:
djverab [1.8K]3 years ago
7 0

Answer:

B. is subject to a smaller net force but same acceleration.

Explanation:

F = m*a

So because our force applied is constant from the women pulling on the rope which means the acceleration is the same on both the 4kg create and the 6kg create. The only thing that changes here is the mass of the creates, so there is more tension force between the women and the 6kg create then there is between the 4kg create and the 6kg. It takes less force to move the 4kg create therefore the tension force is less between the two creates.

Anastasy [175]3 years ago
7 0

Answer:

Explanation:

We know that when force (F) is applied then both the crate will move together so both have same acceleration.

And from Newton's 2 nd law we have:

F= ma , where m= mass of crate and a is acceleration.

Now for crate of mass 4 kg we have:

F = ma = 4a Newton.    

For the crate of mass 6 kg we have:

F = ma = 6a Newton.    

Hence the crate having less mass is subjected with smaller net force .

Hence from the above we can conclude that the correct answer is option 3 which is : is subjected to a smaller net force and has the same acceleration.

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What's the value of 57,281 joules in Btu? A. 54.3 Btu B. 14.2 Btu C. 28.9 Btu D. 37.7 Btu
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I'm quite sure it is A
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Does anyone know what #2 and #3 is
EleoNora [17]

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He can figure out if they heat to the same temp with the thermometer.

Explanation:

They have different boiling points and heat up at different rates so they would have different temps at the same time

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2 years ago
"A short-wave radio antenna is supported by two guy wires, 150 ft and 170 ft long. Each wire is attached to the top of the anten
Nonamiya [84]

Answer:

The anchor points are 78.37 ft and 111.99 ft

Explanation:

If you look at the attached (Fig 1) you will find that the union of antenna and its guy wires forms two right triangles. To solve problems that involve this kind of triangles, you can apply trigonometric functions (sine, cosine, etc) and Pythagoras Theorem. Trigonometric functions states the relation between angles, sides and hypotenuse of a right triangle. If you look Fig2, considering α angle, "b" is the opposite side, "a" the adjacent side and "c" the hypotenuse. Then

a) Sine (α) = b/c it means opposite side/hypotenuse

b) Cosine (α)= a/c, it means adjacent side/hypotenuse

c) Tangent (α) = b/a opposite side/adjacent side.

Pythagoras theorem states that if you called "a" and "b", the sides of the right triangle, and "c" the hypotenuse, then:

                                      a² + b² = c²    

As the problem states the lengths 150 ft and 170 ft represents the value of the hypotenuse of each triangle and 65° is one of the angles of the triangle with 150 ft hypotenuse. So you can solve this using sin (65°) to find the height of the antenna (h) and then the two distances (x and y,).

Sine (65°) = h/ 150 ft ⇒ Sine (65°) x 150ft = h ⇒ h = 127.9 ft.

To find x : Cosine (65°) = x/ 150 ft ⇒ Cosine (65°) x 150 ft = x

⇒ x = 78.37 ft.

And finally, to find y we can apply Pythagoras theorem

(170 ft)² = (127.9 ft)² + y² ⇒ y² = (170 ft)² - (127.9 ft)² ⇒ y = 111.99 ft

Summarizing, the anchor points are 78.37 ft and 111.99 ft

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