A stunt driver drives a car horizontally off the edge of a cliff at 3.8m/s and reaches the water below 2.5s later.
1 answer:
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The velocity of the submarine immediately after firing the missile is 0.0104 m/s
Explanation:
Mass of the submarine M=50 tonne=
Mass of the missile m=40 kg
velocity of the missile v= 13m/s
we have to calculate the velocity of the submarine after firing
This is the recoil velocity and its expression is derived from the law of conservation of momentum
recoil velocity of the submarine
Answer:
Final temperature is 295K
Explanation:
Where the sample of copper is placed in the water, the heat transferred from the copper is equal that the heat absorbed by the water.
The heat transferred from the copper is:
C××mass×ΔT
Where C is molar heat capacity of copper (24,5J/molK)
Mass is 25,0g
And ΔT is final temperature - initial temperature (X-363K)
Also, the heat absorbed by the water is:
-C××mass×ΔT
Where C is molar heat capacity of water (75,2J/molK)
Mass is 100,0g
And ΔT is final temperature - initial temperature (X-293K)
As heat transferred is equal to heat absorbed:
24,5J/molK××25,0g×(X-363K) = -75,2J/molK×
×100,0g× (X-293K)
9,64X J/K - 3499J = - 417X J/K + 122273J
426,64X J/K = 125772 J
<em>X = 295K</em>
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Final temperature is 295K
I hope it helps!