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3 years ago

Over 44% of the 30 students in a class read a

Mathematics

1 answer:

Yakvenalex [24]3 years ago

5 0

Answer:

I got 13.2 but you could probably round it to 13.

Step-by-step explanation:

44 percent *30 =

(44:100)*30 =

(44*30):100 =

1320:100 = 13.2

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Find a positive angle less than one rotation that is coterminal with –308°.

Anna35 [415]

The answer would be -72 cuz -308 + -72 is -360 which is a whole circle

warningggg: if this is a home quiz your taking , don't put my answer down cuz there is a 30% chance my answer is wrongdoing

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3 years ago

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Can someone help me on question 7b ?

Marizza181 [45]

Lengths are given to 1dp so the biggest that the lengths could be is 4.65cm and 5.35cm. if you use pythagoras on these to find hypotenuse, this is the upper bound.

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3 years ago

Tallulah has 40 dimes and some nickels. The total value of her change is $5.00. How many nickels does Tallulah have?

Verdich [7]

40 dimes is $4.00. you would need $1 in nickles. 2 nickles is 10 cents. so you would need 20 nickles.

10x+160=300
-160 -160
10x=140
divide both sides by 10
x=14
$14

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3 years ago

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1) Lithium isotope rations are important to medicine, the 6Li/7Li ratio in a standard reference material was measured several ti

uysha [10]

Answer:

1) $0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

b) $ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=0.0826052$ represent the sample mean

$\mu$ population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size

Part 1

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=5-1=4$

The Confidence level is 0.95 or 95%, and the significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ , the critical value would be using the t distribution with 4 degrees of freedom: $t_{\alpha/2}=2.776$