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lapo4ka [179]
3 years ago
13

Which force keeps you near earths surface?

Physics
1 answer:
satela [25.4K]3 years ago
6 0
Gravity holds us to the surface of the Earth and maintains our atmosphere by being wrapped around our planet. An object's weight is a measure of the gravitational force acting on it. ;)
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If the emf of the battery is 12 v and each resistance is 4 ω, what power is consumed by bulb b?
dlinn [17]
P = V^2/R
= 144/4
= 36 watts
6 0
4 years ago
How did the horizontal velocity vector component change during the flight of the cannonball in the simulation
arlik [135]

Answer:

<em>The horizontal velocity vector of the canonball does not change at all, but is constant throughout the flight.</em>

Explanation:

First, I'll assume this is a projectile simulation, since no simulation is shown here. That been the case, in a projectile flight, there is only a vertical component force (gravity) acting on the body, and no horizontal component force on the body. The effect of this on the canonball is that the vertical velocity component on the canonball goes from maximum to zero at a deceleration of 9.81 m/s^2, in the first half of the flight. And then zero to maximum at an acceleration of 9.81 m/s^2 for the second half of the flight before hitting the ground. <em>Since there is no force acting on the horizontal velocity vector of the canonball, there will be no acceleration or deceleration of the horizontal velocity component of the canonball. This means that the horizontal velocity component of the canonball is constant throughout the flight</em>

7 0
4 years ago
A force of 5 N accelerates an object. The object’s mass is 50 g. What is the acceleration of the object? (Formula: F=ma)
goldfiish [28.3K]

Answer:

100 m/s²

Explanation:

First, convert to SI units:

50 g = 0.050 kg

Now plug into the formula:

F = ma

5 N = (0.050 kg) a

a = 100 m/s²

4 0
4 years ago
Read 2 more answers
A 600kg car is at rest , and then accelerates to 5n/s what is the original kinetic energy?
lubasha [3.4K]
M = 600 kg
u = 0 (as the car was at rest initially)
v = 5 m/s
Initial kinetic energy = ½mu²
= ½×600×0
= 0
Final kinetic energy = ½mv²
= ½×600×25
= 7500 J
7 0
4 years ago
An airplane cruises at 850 km/h relative to the air. It is flying from Denver, Colorado, due west to Reno, Nevada, a distance of
skad [1K]

Answer:

difference in flight time= 0.3023 hour

Explanation:

The question is incomplete, but I found it in your textbook.

Spped of aircraft = 850 km/h

Opposing speed of wind = 90km/h

Hence, the net speed when it's travelling west = 850 - 90 = 760 km/hr

The distance covered = 1200km

time taken = distance/ time = 1200/ 760 = 1.5789 hours

When coming back, the speed of the wind is complementary to the speed of the aircraft so

net speed when it's coming back = 850 +90 = 940 km/hr

time taken in this instance = 1200/ 940 = 1.2765 hours

Hence, the difference in flight time= 1.5789 - 1.2765 = 0.3023 hour

8 0
3 years ago
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