Question

A 42 cm long solenoid, 1.8 cm in diameter, is to produce a 0.030 T magnetic field at its center. If the maximum current is 4.5 A, how many turns must the solenoid have?

Answer 1

Answer:

The number of turns is $2.2 \times 10^{3}$

Explanation:

The computation of the number of turns is shown below:

$B = \mu o \frac{N}{L}I \\\\N = \frac{BL}{\mu oI}\\\\= \frac{0.030 T \times 0.42}{4\pi\times 10^{-7} (4.5)} \\\\= 2.2 \times 10^{3}$

hence, the number of turns is $2.2 \times 10^{3}$