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4vir4ik [10]
3 years ago
11

An airplane cruises at 850 km/h relative to the air. It is flying from Denver, Colorado, due west to Reno, Nevada, a distance of

1200 km, and will then return. There is a steady 90km/h wind blowing to the east.
Physics
1 answer:
skad [1K]3 years ago
8 0

Answer:

difference in flight time= 0.3023 hour

Explanation:

The question is incomplete, but I found it in your textbook.

Spped of aircraft = 850 km/h

Opposing speed of wind = 90km/h

Hence, the net speed when it's travelling west = 850 - 90 = 760 km/hr

The distance covered = 1200km

time taken = distance/ time = 1200/ 760 = 1.5789 hours

When coming back, the speed of the wind is complementary to the speed of the aircraft so

net speed when it's coming back = 850 +90 = 940 km/hr

time taken in this instance = 1200/ 940 = 1.2765 hours

Hence, the difference in flight time= 1.5789 - 1.2765 = 0.3023 hour

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A car generates 2,552 N and weighs 2,250 pounds. what is the rate of acceleration
Lilit [14]
Ans: a = 2.50 m/s^2

Explanation:
First convert the mass in its standard unit i.e. kilogram(kg):
2250 lbs = 1020.583kg

Next use Newton's Second law:
F = ma

Where F = 2552N
m = 1020.583kg

=> a = (2552/1020.583)
a = 2.50 m/s^2
6 0
3 years ago
What is the gravitational force on a 70kg that is 6.38x10^6m above the earths surface
NARA [144]

Answer:

171.5 N

Explanation:

The gravitational force on an object due to the Earth is given by

F=mg

where

m is the mass of the object

g is the acceleration due to gravity

The acceleration due to gravity at a certain height h above the Earth is given by

g=\frac{GM}{(R+h)^2}

where:

G is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

R=6.37\cdot 10^6 m is the Earth's radius

Here,

h=6.38\cdot 10^6  m

So the acceleration due to gravity is

g=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})}{(6.37\cdot 10^6 + 6.38\cdot 10^6)^2}=2.45 m/s^2

We know that the mass of the object is

m = 70 kg

So, the gravitational force on it is

F=mg=(70)(2.45)=171.5 N

5 0
3 years ago
A 0.272-kg volleyball approaches a player horizontally with a speed of 12.6 m/s. The player strikes the ball with her fist and c
Nady [450]

(a) +9.30 kg m/s

The impulse exerted on an object is equal to its change in momentum:

I= \Delta p = m \Delta v = m (v-u)

where

m is the mass of the object

\Delta v is the change in velocity of the object, with

v = final velocity

u = initial velocity

For the volleyball in this problem:

m = 0.272 kg

u = -12.6 m/s

v = +21.6 m/s

So the impulse is

I=(0.272 kg)(21.6 m/s - (-12.6 m/s)=+9.30 kg m/s

(b) 155 N

The impulse can also be rewritten as

I=F \Delta t

where

F is the force exerted on the volleyball (which is equal and opposite to the force exerted by the volleyball on the fist of the player, according to Newton's third law)

\Delta t is the duration of the collision

In this situation, we have

\Delta t = 0.06 s

So we can re-arrange the equation to find the magnitude of the average force:

F=\frac{I}{\Delta t}=\frac{9.30 kg m/s}{0.06 s}=155 N

6 0
3 years ago
Give an example in which a small force exerts a large torque. give another example in which a large force exerts a small torque.
goldenfox [79]
<span>Since the torque involves the product of force times lever arm, a small force can exert a greater torque than a larger force if the small force has a large enough lever arm.

With a large force exerts a small torque is a gate, hinged in its vertical line (axis). When pushed from a point near to the hinge, a very large amount is needed to open the gate.
</span><span>
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3 0
3 years ago
Read 2 more answers
Earth has a magnetic dipole moment of 8.0 × 1022 J/T. (a) What current would have to be produced in a single turn of wire extend
Lelechka [254]

Answer:

Answer is

A. I = 6.3×10^8 A

B. Yes

C. No

Refer below.

Explanation:

Refer to the picture for brief explanation.

7 0
4 years ago
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