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Evgen [1.6K]
4 years ago
6

Determine the quantity of heat transferred by 20.0 grams of water where the temperature of the water changes from 65°C to 20°C,

the temperature of the room
Physics
1 answer:
dexar [7]4 years ago
5 0

Answer:

3780J

Explanation:

Data obtained from the question include:

M (mass) = 20g

T1 (initial temperature) = 65°C

T2 (final temperature) = 20°C

ΔT (change in temperature) =

T1 — T2 (since we are cooling)

ΔT = 65 — 20 = 45°C

C (specific heat capacity) = 4.2J/g°C

Q (heat) =?

Q = MCΔT

Q = 20 x 4.2 x 45

Q = 3780J

Therefore, the heat transferred is 3780J

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The deck of a bridge is suspended 235 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Aleks04 [339]

Answer:

(a) 1, average velocity = -65.6 m/s

   2, average velocity = -64.8 m/s

   3, average velocity = -64.16 m/s

(b) The instantaneous velocity is -96 m/s

Explanation:

(a)

Average velocity is given  by;

y(t_2,t_1) = \frac{y(t_2) - y(t_1)}{t_2-t_1}

(1)

y(2.1,2) = \frac{(235-16*2.1^2) - (235-16*2^2)}{2.1-2}\\\\ y(2.1,2) = -65.6 \ m/s

(2)

y(2.05,2) = \frac{(235-16*2.05^2) - (235-16*2^2)}{2.05-2}\\\\ y(2.05,2) = -64.8 \ m/s

(3)

y(2.01,2) = \frac{(235-16*2.01^2) - (235-16*2^2)}{2.01-2}\\\\ y(2.01,2) = -64.16 \ m/s

b. y = 235 - 16t²

The instantaneous velocity is given by;

v = dy /dt

dy / dt = -32t

when t = 3 s

v = -32(3)

v = -96 m/s

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Read 2 more answers
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