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katen-ka-za [31]
4 years ago
15

The polynomial p(x)=2x^3-x^2-25x-12 has a known factor of (x+3). Rewrite p(x) as a product of linear factors.

Mathematics
1 answer:
katrin2010 [14]4 years ago
8 0

Answer:

p(x) = (x + 3) (2x + 1) (x − 4)

Step-by-step explanation:

One way to find the other factor is long division (see attached).

Another way is to multiply x + 3 by ax² + bx + c, then match the result to p(x).

(x + 3) (ax² + bx + c)

ax³ + bx² + cx + 3ax² + 3bx + 3c

ax³ + (b+3a)x² + (c+3b)x + 3c

a = 2, b = -7, c = -4

Therefore:

p(x) = (x + 3) (2x² − 7x − 4)

Factoring:

p(x) = (x + 3) (2x + 1) (x − 4)

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Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures (6x+20)^{\circ} and (x+100)^{\circ} are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16

Then

(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}

17. Two parallel lines are cut by transversal. Angles with measures (2x+12)^{\circ} and (3x-22)^{\circ} are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34

Then

(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}

18. Two parallel lines are cut by transversal. Angles with measures (6x-7)^{\circ} and (5x+10)^{\circ} are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

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Then

(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}

19. The diagram shows two complementary angles with measures 2x^{\circ} and 56^{\circ}. The measures of complementary angles add up to 90^{\circ}, then

2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17

Hence,

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Check:

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20. Angles \angle 1 and \angle 2 are vertical angles. By vertical angles theorem, vertical angles are congruent, so

m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4

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m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}

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Therefore,

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