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3 years ago

Can anyone explain how tides work

2 answers:

7 0

<span> the moon's gravitational force pulls on water in the oceans so that there are "bulges" in the ocean on both sides of the planet. The moon pulls water toward it, and this causes the bulge toward the moon. hope this helps (:</span>

Mila [183]3 years ago

6 0

The position of the sun and the moon affect how high the tide is

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A series combination of two resistors, 7.25 ω and 4.03 ω, is connected to a 9.00 v battery.

almond37 [142]

a. $11.28\Omega$

The equivalent resistance of a series combination of two resistors is equal to the sum of the individual resistances:

$R_{eq}=R_1 + R_2$

In this circuit, we have

$R_1 = 7.25 \Omega\\R_2 = 4.03 \Omega$

Therefore, the equivalent resistance is

$R_{eq}=7.25 \Omega + 4.03 \Omega=11.28 \Omega$

b. 5.8 V, 3.2 V

First of all, we need to determine the current flowing through each resistor, which is given by Ohm's law:

$I=\frac{V}{R_{eq}}$

where V = 9.00 V and $R_{eq}=11.28 \Omega$ . Substituting,

$I=\frac{9.00 V}{11.28 \Omega}=0.8 A$

Now we can calculate the potential difference across each resistor by using Ohm's law again:

$V_1 = I R_1 = (0.8 A)(7.25 \Omega)=5.8 V$

$V_2 = I R_2 = (0.8 A)(4.03 \Omega)=3.2 V$

4 0

3 years ago

Can someone help because I am very confused

Rzqust [24]

I can't see ot carefuly

3 0

3 years ago

Solvents are the substances that dissolve solutes; therefore, solvents are always liquids.

Nina [5.8K]

False, although they are usually a liquid. Solvents can be a solid or gas as well. Also, solutes can be in any state as well.

4 0

3 years ago

A force of 3600 N is exerted on a piston that has an area of 0.030 m2. What force is exerted on a second piston that has an area

Airida [17]

For Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:
$p_1 = p_2$
which becomes
$\frac{F_1}{A_1}= \frac{F_2}{A_2}$
where
$F_1=3600 N$ is the force on the first piston
$A_1=0.030 m^2$ is the area of the first piston
$F_2$ is the force on the second piston
$A_2=0.015 m^2$ is the area of the second piston

If we rearrange the equation and we use these data, we can find the intensity of the force on the second piston:
$F_2=F_1 \frac{A_2}{A_1}=(3600 N) \frac{0.015 m^2}{0.030 m^2}= 1800 N$

7 0

3 years ago

Read 2 more answers

Need help guys please

goldenfox [79]

Answer:

6.378 * 10^6 m

Explanation:

Radius = 6378 km

Changing in metres

6378 km = 6378000 m

Now in scientific notation

= 6.378 * 10 ^ 6 m

5 0

3 years ago