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Goshia [24]
3 years ago
7

Which color wave has the largest frequency? n purple red blue orange green

Physics
1 answer:
sweet [91]3 years ago
3 0

Answer: purple

Explanation:

There is an inverse relation between frequency f and wavelength \lambda:

f=\frac{c}{\lambda}

Where c=3(10)^{8} m/s is the speed of light in vacuum

This means:

If \lambda increases f decreases and <u>if \lambda decreases f increases.</u>

In other words, the color wave with the largest frequency is the one with the lowest wavelength.

In this sense, the wavelength for each color is:

\lambda_{purple} \approx 400(10)^{-9}m

\lambda_{blue} \approx 470(10)^{-9}m

\lambda_{green} \approx 550(10)^{-9}m

\lambda_{orange} \approx 615(10)^{-9}m

\lambda_{red} \approx 700(10)^{-9}m

As we can see, purple has the smallest wavelength, hence the largest frequency.

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Answer:

The solar nebula became hot and dense because of that it pulling in more gas. This flattened into a rotating disk. It  spun  faster and faster, forming the Sun.

Explanation:

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A pendulum is used in a large clock. The pendulum has a mass of 2 kg. If the pendulum is moving at a speed of 2.9 m/s when it re
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This is a classic example of conservation of energy. Assuming that there are no losses due to friction with air we'll proceed by saying that the total energy mus be conserved.
E_m=E_k+E_p
Now having information on the speed at the lowest point we can say that the energy of the system at this point is purely kinetic:
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It hasn't changed! So inserting this into the equation relating the total energy at the highest point we'll have:
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3 years ago
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A 117 kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 62.
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Answer:

I_syst = 278.41477 kg.m²

Explanation:

Mass of platform; m1 = 117 kg

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Moment of inertia here is;

I1 = m1•r²/2

I1 = 117 × 1.61²/2

I1 = 151.63785 kg.m²

Mass of person; m2 = 62.5 kg

Distance of person from centre; r = 1.05 m

Moment of inertia here is;

I2 = m2•r²

I2 = 62.5 × 1.05²

I2 = 68.90625 kg.m²

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Distance of Dog from centre; r = 1.43 m

I3 = 28.3 × 1.43²

I3 = 57.87067 kg.m²

Thus,moment of inertia of the system;

I_syst = I1 + I2 + I3

I_syst = 151.63785 + 68.90625 + 57.87067

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8 0
3 years ago
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Answer:

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Calculate the orbital period of a dwarf planet found to have a semimajor axis of a = 4.0x 10^12 meters in seconds and years.
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Explanation:

We have,

Semimajor axis is 4\times 10^{12}\ m

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Since,

1\ s=3.17\times 10^{-8}\ \text{years}\\\\4.37\times 10^9\ s=4.37\cdot10^{9}\cdot3.17\cdot10^{-8}\\\\4.37\times 10^9\ s=138.52\ \text{years}

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