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Goshia [24]
4 years ago
7

Which color wave has the largest frequency? n purple red blue orange green

Physics
1 answer:
sweet [91]4 years ago
3 0

Answer: purple

Explanation:

There is an inverse relation between frequency f and wavelength \lambda:

f=\frac{c}{\lambda}

Where c=3(10)^{8} m/s is the speed of light in vacuum

This means:

If \lambda increases f decreases and <u>if \lambda decreases f increases.</u>

In other words, the color wave with the largest frequency is the one with the lowest wavelength.

In this sense, the wavelength for each color is:

\lambda_{purple} \approx 400(10)^{-9}m

\lambda_{blue} \approx 470(10)^{-9}m

\lambda_{green} \approx 550(10)^{-9}m

\lambda_{orange} \approx 615(10)^{-9}m

\lambda_{red} \approx 700(10)^{-9}m

As we can see, purple has the smallest wavelength, hence the largest frequency.

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S the work done on Amanda's car while speeding up (i) greater than, (ii) less than, or (iii) the same as the work done on Bertha
ankoles [38]

Answer:

Explanation:

Mass of amanda and bertha car = Ma = Mb

Initial velocity of amanda, ua = 10 m/s

Final velocity of amanda, va = 20 m/s

Initial velocity of bertha, ub = 20 m/s

Final velocity of bertha, vb = 30 m/s

Workdone = change in Energy = 1/2 mv^2 - 1/2 mu^2

Ea = Ma × 1/2 × (20^2 - 10^2)

= Ma × 150

= 150 Ma J

Workdone = change in Energy = 1/2 mv^2 - 1/2 mu^2

Eb = Mb × 1/2 × (30^2 - 20^2)

= Mb × 250

= 250 Mb J

Option ii. Less than. Thus this is because the workdone by amanda car (150Ma) is less than the workdone in berthas car (250Mb).

B.

Impulse, p = force × time

p = Mass × change in velocity

pa = Ma × va - Ma × ua

= Ma × (20 - 10)

= 10 × Ma

= 10 Ma

p = Mass × change in velocity

pa = Mb × vb - Mb × ub

= Mb × (30 - 20)

= 10 × Mb

= 10 Mb

Option iii. The same as.

The impulse as seen above is the same in amanda car (10Ma) as the same with bertha (10Mb)

7 0
4 years ago
Amy walks 3 m from her desk to the teacher's desk. From the teacher's desk, she then walks 4 m in the opposite direction to the
Reptile [31]
I don't know what the tables you have look like but her <span>displacement</span> would be -1m

4 0
3 years ago
Read 2 more answers
These questions !plz !! i need help!!!
Nataly_w [17]

(6) Wagon B is at rest so it has no momentum at the start. If <em>v</em> is the velocity of the wagons locked together, then

(140 kg) (15 m/s) = (140 kg + 200 kg) <em>v</em>

==>   <em>v</em> ≈ 6.2 m/s

(7) False. If you double the time it takes to perform the same amount of work, then you <u>halve</u> the power output:

<em>E</em> <em>/</em> (2<em>t </em>) = 1/2 × <em>E/t</em> = 1/2 <em>P</em>

<em />

3 0
3 years ago
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You have a stopped pipe of adjustable length clo
faltersainse [42]

Answer:

Length of pipe = 0.057 meter

Explanation:

Speed of a transverse wave on a string

v = \sqrt{\frac{F}{\mu} }

where F is the tension in string and \mu is the mass per unit length

Thus,

\mu = \frac{m}{L}

Substituting the given values we get -

\mu = \frac{7.25 * 10^{-3}}{0.62}\\mu = 0.0117 \frac{Kg}{m}

Speed of a transverse wave on a string

v = \sqrt{\frac{4510}{0.0117} } \\v = 620.86 \frac{m}{s}

For third harmonic wave , frequency is equal to

f = \frac{nv}{2L}

Substituting the given values, we get -

f = \frac{3 * 620.86}{2 * 0.62} \\f = 1502.08

Length of pipe

L = \frac{nv}{4 f}

Substituting the given values we get

n = 1 for first harmonic wave

L = \frac{344* 1}{4*1502.08} \\L = 0.057

Length of pipe = 0.057 meter

5 0
4 years ago
Which are uses of convex mirrors? Check all that apply.
Serga [27]

Answer:

Its B, C, E

Explanation:

Have a great day everyone:)

3 0
3 years ago
Read 2 more answers
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