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Goshia [24]
3 years ago
7

Which color wave has the largest frequency? n purple red blue orange green

Physics
1 answer:
sweet [91]3 years ago
3 0

Answer: purple

Explanation:

There is an inverse relation between frequency f and wavelength \lambda:

f=\frac{c}{\lambda}

Where c=3(10)^{8} m/s is the speed of light in vacuum

This means:

If \lambda increases f decreases and <u>if \lambda decreases f increases.</u>

In other words, the color wave with the largest frequency is the one with the lowest wavelength.

In this sense, the wavelength for each color is:

\lambda_{purple} \approx 400(10)^{-9}m

\lambda_{blue} \approx 470(10)^{-9}m

\lambda_{green} \approx 550(10)^{-9}m

\lambda_{orange} \approx 615(10)^{-9}m

\lambda_{red} \approx 700(10)^{-9}m

As we can see, purple has the smallest wavelength, hence the largest frequency.

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Steve and Jose drove Jose's car to the beach during Spring Break. The 495 kilometer drive took them 8 hours and 30 minutes. What
Vaselesa [24]

Answer:

58.24 Km/h.

Explanation:

From the question given above, the following data were obtained:

Distance (d) = 495 Km

Time (t) = 8 h 30 mins

Speed (S) =?

Next, we shall express 8 hours 30 mins to hours.

We'll begin by convert 30 mins to hour.

60 mins = 1 h

Therefore,

30 mins = 30 mins × 1 h/ 60 mins

30 mins = 0.5 hour.

Thus,

8 h 30 min = 8 + 0.5 = 8.5 hours

Speed is define as the distance travelled per unit time. Mathematically, it is expressed as:

Speed = Distance /time

With the above formula, we can obtain the speed as shown below:

Distance (d) = 495 Km

Time (t) = 8.5 hour

Speed (S) =?

Speed = Distance /time

Speed = 495 Km / 8.5 hour

Speed = 58.24 Km/h

Thus, the speed is 58.24 Km/h.

3 0
3 years ago
Why do cells undergo mitosis?
avanturin [10]
 <span>Cells undergo mitosis for three main reasons: 
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5 0
3 years ago
Read 2 more answers
A test charge of 13 mC is at a point P where an external electric field is directed to the right and has a magnitude of 4 3 106
LenKa [72]

Answer:

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.

Explanation:

From coulomb's law, F = Eq

Thus,

F = E₁q₁

F = E₂q₂

Then

E₂q₂ = E₁q₁

E_2 = \frac{E_1q_1}{q_2}

where;

E₂ is the external electric field due to second test charge = ?

E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C

q₁ is the first test charge = 13 mC

q₂ is the second test charge = 23 mC

Substitute in these values in the equation above and calculate E₂.

E_2 = \frac{4*10^6*13}{23} = 2.26 *10^6 \ N/C

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.

However, the direction of the external field is still to the right.

8 0
3 years ago
A ball is dropped from rest at a point 12 m above the ground into a smooth, frictionless chute. The ball exits the chute 2 m abo
Nonamiya [84]

Answer:

29,7 m

Explanation:

We need to devide the problem in two parts:

A)  Energy

B) MRUV

<u>Energy:</u>

Since no friction between pint (1) and (2), then the energy conservatets:

Energy = constant ----> Ek(cinética) + Ep(potencial) = constant

Ek1 + Ep1 = Ek2 + Ep2

Ek1 = 0  ; because V1 is zero (the ball is "dropped")

Ep1 = m*g*H1

Ep2= m*g*H2

Then:

Ek2  = m*g*(H1-H2)

By definition of cinetic energy:

m*(V2)²/2 = m*g*(H1-H2) --->  V2 = \sqrt{(2*g*(H1-H2)}

Replaced values:  V2 = 14,0 m/s

<u>MRUV:</u>

The decomposition of the velocity (V2), gives a for the horizontal component:

V2x = V2*cos(α)

Then the traveled distance is:

X = V2*cos(α)*t.... but what time?

The time what takes the ball hit the ground.

Since: Y3 - Y2 = V2*t + (1/2)*(-g)*t²

In the vertical  axis:

Y3 = 0 ; Y2 = H2 = 2 m

Reeplacing:

-2 = 14*t + (1/2)*(-9,81)*t²

solving the ecuation, the only positive solution is:

t = 2,99 sec ≈ 3 sec

Then, for the distance:

X = V2*cos(α)*t = (14 m/s)*(cos45°)*(3sec) ≈ 29,7 m

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3 years ago
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Answer: B

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