Question

Question 12 (5 points) During an experiment a student traps 0.1941 g of an unknown gas in a 175.6 mL container at 298.1 K and a pressure of 0.9648 atm. What would be the volume of the gas in mL at STP?

Answer 1

Answer:

V₂ = 155.2 mL

Explanation:

Given data:

Initial volume =175.6 mL

Initial pressure =0.9648 atm

Initial temperature = 298.1 K

Final temperature = 273 K

Final volume =?

Final pressure = 1 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂  /T₁P₂

V₂ = 0.9648 atm × 175.6 mL × 273 k / 298.1 K× 1 atm

V₂ = 46251.4 atm. k. mL/ 298.1 K× 1 atm

V₂ = 155.2 mL