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pogonyaev
3 years ago
13

Think and discuss: Why do you think the rate of temperature change does not stay constant over time? If possible, discuss your a

nswer with your teacher and classmates.
Physics
1 answer:
gogolik [260]3 years ago
6 0

Because the temperature of the place its contained in is constantly changing, for example, if you put a room temperature item in the fridge it will become cold, or whatever the temperature you set your fridge to.

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3. Neha travels 4 m towards the north, 3m towards the east, and then 7 m towards south, find the displacement and total distance
Digiron [165]

Answer:

Explanation:

Explanation: total displacement =3√2m. and total distance covered=14m. I hope this is right and helps u.

7 0
3 years ago
The series in the He spectrum that corresponds to the set of transitions where the electron falls from a higher level to the nf
Galina-37 [17]
Ok so here is the thing. It is necessary to introduce the atomic number Z into the following equation and the reason for that is that we are not working here with hydrogen (H). It will go like this:  
<span>E=(2.18×10^-18 J)(Z^2 )|1/(ni^2 )-1/(nf^2 )| </span>
<span>E=(2.18×10^-18 J)(2^2 )|1/(6 ^2 )-1/(4 ^2 )|=3.02798×10^-19 J </span>

<span>After that we need to plug the E value calculated into the equation. Remember that the wavelength is always positive:</span>

<span>E=hc/λ 3.02798×10^-19 J=hc/λ λ=6.56×10^-7 m </span>

so 6.56×10^-7 m or better written 656 nm is in the visible spectrum
7 0
3 years ago
In which region of the ear does resonance allow the brain to interpret sound answer
lakkis [162]
I'm not too sure what your asking but here are two answers that may help.
The ear drum amplifies the vibrations.
The cochlea changes vibrations into electric signals.
7 0
3 years ago
A point charge q is located at the center of a spherical shell of radius a that has a charge −q uniformly distributed on its sur
muminat

Answer:

a) E = 0

b) E =  \dfrac{k_e \cdot q}{ r^2 }

Explanation:

The electric field for all points outside the spherical shell is given as follows;

a) \phi_E = \oint E \cdot  dA =  \dfrac{\Sigma q_{enclosed}}{\varepsilon _{0}}

From which we have;

E \cdot  A =  \dfrac{{\Sigma Q}}{\varepsilon _{0}} = \dfrac{+q + (-q)}{\varepsilon _{0}}  = \dfrac{0}{\varepsilon _{0}} = 0

E = 0/A = 0

E = 0

b) \phi_E = \oint E \cdot  dA =  \dfrac{\Sigma q_{enclosed}}{\varepsilon _{0}}

E \cdot  A  = \dfrac{+q }{\varepsilon _{0}}

E  = \dfrac{+q }{\varepsilon _{0} \cdot A} = \dfrac{+q }{\varepsilon _{0} \cdot 4 \cdot \pi \cdot r^2}

By Gauss theorem, we have;

E\oint dS =  \dfrac{q}{\varepsilon _{0}}

Therefore, we get;

E \cdot (4 \cdot \pi \cdot r^2) =  \dfrac{q}{\varepsilon _{0}}

The electrical field outside the spherical shell

E =  \dfrac{q}{\varepsilon _{0} \cdot (4 \cdot \pi \cdot r^2) }= \dfrac{q}{4 \cdot \pi \cdot \varepsilon _{0} \cdot r^2 }=  \dfrac{q}{(4 \cdot \pi \cdot \varepsilon _{0} )\cdot r^2 }

k_e=  \dfrac{1}{(4 \cdot \pi \cdot \varepsilon _{0} ) }

Therefore, we have;

E =  \dfrac{k_e \cdot q}{ r^2 }

5 0
3 years ago
If a car is traveling on the highway at a constant velocity, the force that pushes the car forward must be A. equal to the weigh
Gala2k [10]

the correct answer is c

4 0
3 years ago
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