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2 years ago

What are the two most important traits between a whale and a shark?

Physics

1 answer:

nordsb [41]2 years ago

8 0

Answer:

Both are aquatic animals and are hunters

Explanation:

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How long does it take for light from the sun to reach earth

MrRa [10]

8 minutes and 20 seconds

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3 years ago

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Which gives the correct relationship for kinetic energy?

lisabon 2012 [21]

Answer:

MV/2

Explanation:

Because that is what I've been taught

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3 years ago

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A sinusoidal traveling wave is generated on a string by an oscillating source that completes 116 cycles per minute. What is the

slava [35]

Answer:

$\lambda =6.32\ cm$

Explanation:

given,

number of cycle complete (f) = 116 cycles per minute

wavelength observed at 11 m in 1.5 m.

$v = \dfrac{distance}{time}$

$v = \dfrac{11}{1.5}$

v = 7.33 m/s

$\lambda = \dfrac{v}{f}$

$\lambda = \dfrac{7.33}{116}$

$\lambda =0.0632\ m$

$\lambda =6.32\ cm$

The wavelength of the wave is equal to $\lambda =6.32\ cm$

6 0

3 years ago

A train reaches a speed of 35.0 m/s after accelerating at a rate of 5.00 m/s2 over a distance of 40.0 m. What was the train’s in

MatroZZZ [7]

Answer:

Initial velocity, U = 28.73m/s

Explanation:

Given the following data;

Final velocity, V = 35m/s

Acceleration, a = 5m/s²

Distance, S = 40m

To find the initial velocity (U), we would use the third equation of motion.

V² = U² + 2aS

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

S represents the displacement measured in meters.

Substituting into the equation, we have;

35² = U + 2*5*40

1225 = U² + 400

U² = 1225 - 400

U² = 825

Taking the square root of both sides, we have;

Initial velocity, U = 28.73m/s

5 0

2 years ago

3. Una cuerda de guitarra tiene 60 cm de longitud y una masa de 0.05 kg de masa. Si se tensiona mediante una fuerza de 20 N. La

jok3333 [9.3K]

Answer:

f1 = 12.90 Hz

Explanation:

To calculate the first harmonic frequency you use the following formula for n = 1:

$f_n=\frac{n}{2L}\sqrt{\frac{T}{M/L}}$

$f_1=\frac{1}{2L}\sqrt{\frac{T}{M/L}}$ ( 1 )

It is necessary that the unist are in meters, then you have:

L: length of the string = 60cm = 0.6m

M: mass of the string = 0.05kg

T: tension on the string = 20 N

you replace the values of L, M and T in the expression (1) for getting f1:

$f_1=\frac{1}{2(0.6m)}\sqrt{\frac{20N}{0.05kg/0.6m}}=12.90\ Hz$

Hence, the first harmonic has a frequency of 12.90 Hz

4 0

3 years ago