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ivolga24 [154]
2 years ago
9

A house is advertised as having 1580 square feet under roof. What is the area of this house in square meters?

Physics
1 answer:
Natasha2012 [34]2 years ago
4 0

The area of the house will be 146.78 in square meters

What we have given in the question is that there is one house whose area is measured in square feet which is 1580 square feet, and we have to convert that area in square meter.

Now, To convert the area in square meter we must divide the area given in square feet by a constant which is 10.764.

Area in square meter = Area in square feet / 10.764

Area in square meter = 1580 / 10.764 square meter

Area in square meter = 146.78 square mete

Thus we conclude that You must divide the area given in square feet by 10.764 to convert Square feet to Square meters and vice versa for the opposite and after calculation we found that area which is 1580 square feet will be 146.78 in magnitude in square meters

Learn more about Area Calculation here:

brainly.com/question/23422101

#SPJ10

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A 1.20 kg water balloon will break if it experiences more than 530 N of force. Your 'friend' whips the water balloon toward you
soldi70 [24.7K]

Answer:

t = 0.029s

Explanation:

In order to calculate the interaction time at the moment of catching the ball, you take into account that the force exerted on an object is also given by the change, on time, of its linear momentum:

F=\frac{\Delta p}{\Delta t}=m\frac{\Delta v}{\Delta t}       (1)

m: mass of the water balloon = 1.20kg

Δv: change in the speed of the balloon = v2 - v1

v2: final speed = 0m/s (the balloon stops in my hands)

v1: initial speed = 13.0m/s

Δt: interaction time = ?

The water balloon brakes if the force is more than 530N. You solve the equation (1) for Δt and replace the values of the other parameters:

|F|=|530N|= |m\frac{v_2-v_1}{\Delta t}|\\\\|530N|=| (1.20kg)\frac{0m/s-13.0m/s}{\Delta t}|\\\\\Delta t=0.029s

The interaction time to avoid that the water balloon breaks is 0.029s

5 0
3 years ago
A rifle is aimed horizontally at a target 49 m away. the bullet hits the target 2.3 cm below the aim point. part a what was the
Nezavi [6.7K]

We use the equation of motion for vertical component,

s_{y} = u_{y} t+\frac{1}{2} gt^2.

Here, s_{y}   is displacement of bullet, u_{y}  is vertical initial velocity of bullet which is equal to zero because bullet was fired horizontally, and t is time of flight.

Therefore,

s_{y} =\frac{1}{2}gt^2

Given, s_{y} =2.3 \ cm = 2.3 \times 10^{-2} \ m

Substituting the values, we get time of flight

2.3 \times 10^{-2} \ m = \frac{1}{2} \times 9.8 \ m/s^2 \times t^2 \\\\ t =\sqrt{46.94 \times 10^{-4} \ s } = 0.069 \ s

4 0
3 years ago
Acceleration is defined as the rate of change for which of the following? Question 4 options: time position velocity displacemen
vovangra [49]

Acceleration can be defined as the rate of change in the velocity of an object. Option C is correct.

<h3>What is Acceleration?</h3>
  • It is defined as the rate of change in velocity.
  • It can also be defined as the rate of change in position in a particular direction.

a =  \dfrac {v-u}t\ \ \ \ \rmor}\\\\a = \dfrac {\Delta v }t

Where,

a - acceleration

\Delta v - change in velocity

t - time

Therefore, acceleration can be defined as the rate of change in the velocity of an object.

Learn more about Velocity:

brainly.com/question/2239252

4 0
2 years ago
How long does it take the projectile to reach its highest point in its trajectory?​
NeTakaya

Answer:

It takes about 88 seconds for the cannonball to reach its maximum height (ignoring air resistance).

Explanation:

3 0
3 years ago
Part 1: Fill in the SI unit for each of the following measurements. 1. Time: 2. Length: 3. Mass: 4. Temperature:
Alik [6]

Answer:

1. Time: Second

2. Length: Meter

3. Mass: Kilogram

4. Temperatur: Kelvin

Explanation:

...

3 0
2 years ago
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