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4 years ago

If the frequency of wave is 400 Hz and its

Physics

1 answer:

agasfer [191]4 years ago

8 0

Answer:

D) 1000 m/s

Explanation:

$wavelength = \frac{velocity}{frequency}$

You have the wavelength and frequency, you just need to solve for velocity. You can do this by multiplying each side of the equation by frequency.

Hope this helps.

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Which of the following are relatively unchanged fragments from the early period of planet building in the solar system? a. aster

Inga [223]

Answer:

The answer would be B ........m

5 0

4 years ago

The average intensity of light emerging from a polarizing sheet is 0.775 W/m2, and that of the horizontally polarized light inci

rewona [7]

Answer:

the transmission axis of polarizing sheet makes an angle of $\Theta =26.74^{\circ}$ with the horizontal

Explanation:

We have given that intensity of light incident on the sheet $I_0=0.970W/m^2$

Average intensity of light emerging from a polarizing sheet $I=0.775W/m^2$

We have to find the angle between transmission axis with the horizontal

Intensity of light polarizing from sheet is equal to $I=I_0cos^2\Theta$

So $0.775=0.970cos^2\Theta$

$cos^2\Theta =0.798$

$cos\Theta =0.893$

$\Theta =26.74^{\circ}$

So the transmission axis of polarizing sheet makes an angle of $\Theta =26.74^{\circ}$ with the horizontal

5 0

3 years ago

Two point charges are separated by 6 cm. The attractive force between them is 20 N. Find the force between them when they are se

Scorpion4ik [409]

Answer:

5 N

Explanation:

$F_1$ = 20 N

$r_1$ = 6 cm

$r_2$ = 12 cm

k = Coulomb constat

q = Charge

$\dfrac{F_1}{F_2}=\dfrac{\dfrac{kq_1q_2}{r_1^2}}{\dfrac{kq_2q_2}{r_2^2}}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{12^2}{6^2}\\\Rightarrow \dfrac{F_1}{F_2}=4\\\Rightarrow F_2=\dfrac{F_1}{4}\\\Rightarrow F_2=\dfrac{20}{4}\\\Rightarrow F_2=5\ N$

The force is 5 N

7 0

3 years ago

If a plane can travel 450 miles per hour with the wind and 410 miles per hour against the wind, find the speed of the plane with

BabaBlast [244]

The speed of the plane through the air is 430 mph, and you described a day when the wind was blowing at 20 mph.

8 0

4 years ago

Read 2 more answers

Un bloque de 750 kg es empujado hacia arriba por una pista inclinada 15º respecto de la horizontal. El coeficiente de rozamiento

kotegsom [21]

Answer:

4776.98 N is the minimum force to start the rise.

Explanation:

We can use the first Newton's law to find the minimum force to move the block.

So we will have:

$F-W_{x}-F_{f}=0$

Where:

F is the force
W(x) is the weight of the block in the x direction, W = mg*sin(15)
F(f) is the static friction force (F(f) = μN), μ is the static friction coefficient 0.4.

$F=W_{x}+F_{f}=mgsin(15)+\mu N$

$F=mgsin(15)+\mu mgcos(15)$

$F=mg(sin(15)+\mu cos(15))$

$F=750*9.81(sin(15)+0.4*cos(15))$

$F=4776.98 N$

Therefore 4776.98 N is the minimum force to move the block.

I hope it helps you!

8 0

3 years ago