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lana66690 [7]
2 years ago
10

A machine does 50 J of Work on a 10 Kg Object. What is the Change in the Objects Total Energy?

Physics
1 answer:
Otrada [13]2 years ago
3 0

The change in the total energy of the object is zero (0).

The given parameters:

work done by the machine, W = 50 J

mass of the object, m = 10 kg

To find:

the change in the total energy of the object

The change in the total energy of the object is the difference between the objects initial energy due to its position and the work done on the object.

Based on work energy-theory, the work done on the object is equal to the energy of the object.

  • The energy of the object = work-done on the object
  • The change in total energy = 50 J - 50 J = 0

Thus, the change in the total energy of the object is zero (0).

Learn more here: brainly.com/question/20377140

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A train at rest emits a sound at a frequency of 1057 Hz. An observer in a car travels away from the sound source at a speed of 2
il63 [147K]

Answer:

993.52 Hz

Explanation:

The frequency of sound emitted by the stationery train is 1057 Hz.

The car travels away from the train at 20.6 m/s.

The frequency the observer hears is given by the formula:

f_o = \frac{v - v_o}{v}f

where v = velocity of sound = 343 m/s

vo = velocity of observer

f = frequency from source

This phenomenon is known as Doppler's effect.

Therefore:

f_o = \frac{343 - 20.6}{343} * 1057\\ \\f_o = 322.4 / 343 * 1057\\\\f_o = 993.52 Hz

The frequency heard by the observer is 993.52 Hz.

4 0
3 years ago
A fisherman noticed that a wave strikes the boat side every 5 seconds. The distance between two consecutive crest is 1.5m. What
GrogVix [38]
5/1.5=7 I think that is the answer
8 0
3 years ago
.
eimsori [14]

Explanation:

d =  \frac{1}{2} a {t}^{2}  + vt \\ d = 75 \\ t = 5 \\ v = 0 \\  \\ 75 =  \frac{1}{2}  \times 25a + 0 \\ a = 6 \frac{m}{ {s}^{2} }  \\

7 0
2 years ago
Which of the following changes would cause the fusion rate in the Sun’s core to increase? Check all that apply. View Available H
fredd [130]

Answer:

1. An increase in the core temperature

2. A decrease in the core radius.

Explanation:

The sun is a Main Sequence star. A Main Sequence star is powered by fusing hydrogen into Helium within its core.

For this fusion to take place, a temperature of at least 10 million Kelvin is required, beyond this point, the fusion rate is directly related to the core temperature. If the temperature increases, the fusion rate will greatly increase.

Something similar happens if the core reduces its radius. This can happen at the end of the star's lifetime, shortly before it becomes a red giant. Once the hydrogen is depleted, the core will start to shrink because the force of gravity, and as it gets smaller, gets more compressed, and its temperature increases. The outer layers of remaining Hydrogen that were outside the core now begin to heat up, and as the core continues to shrink, the star gets hot enough to begin the fusion process again, and the fusion rate can even be higher than it was during the first phase of the star, as the star becomes a Red Giant.

7 0
2 years ago
Find the total displacement of a mouse that travels 1.0 m north and then 0.8 m south.
andreev551 [17]
North: 1m
South: 0,8m

Direction:

1m>0,8m 

so mouse moved north

Distance:

1m-0,8m=0,2m

so mouse traveled 0,2m


Answer: The mouse moved 0,2m north.



"Non nobis Domine, non nobis, sed Nomini tuo da gloriam."



Regards M.Y.





3 0
2 years ago
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