A machine does 50 J of Work on a 10 Kg Object. What is the Change in the Objects Total Energy?
1 answer:
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Answer:
W = 2352 J
Explanation:
Given that:
- mass of the bucket, M = 10 kg
- velocity of pulling the bucket, v = 3
- height of the platform, h = 30 m
- time taken, t = 10 min
- rate of loss of water-mass, m =
Here, according to the given situation the bucket moves at the rate,
The mass varies with the time as,
Consider the time interval between t and t + ∆t. During this time the bucket moves a distance
∆x = 3∆t meters
So, during this interval change in work done,
∆W = m.g∆x
<u>For work calculation:</u>
Answer:
Explanation:
We have given the rest mass of SPARTYON = 945 times of mass of electron
We know that mass of electron
So mass of SPARTYON
Speed of light
According to Einstein equation energy is given by
Now according to planks's rule
Energy is given by
, here h is plank's constant
So