Draw the resonance structures for the conjugate base of Phenol (C6H6O). In one sentence, explain why phenol (C6H6O) has a pKa of
10 while cyclohexanol (C6H12O) has a pKa of 16
1 answer:
Answer:
The four resonance structures of the phenoxide ion are shown in the image attached
The conjugate base of cyclohexanol has only one resonance contributor, while
the conjugate base of phenol has four resonance contributors.
Explanation:
In organic chemistry, it is known that structures are more stable if they possess more resonance contributors. The greater the number of contributing canonical structures, the more stable the organic specie. Since the phenoxide ion has four contributing canonical structures, it is quite much more stable than cyclohexanol having only one contributing structure to its conjugate base. Hence the PKa(acid dissociation constant) of phenol is lesser than that of cyclohexanol. The conjugate base of phenol is stabilized by resonance.
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Answer:
Bromobenzoic acid
Explanation:
COOH has higher priority than Br, so the parent name is benzoic acid.
The COOH group is automatically on C1 of the ring, and the other aromatic carbons are numbered sequentially around the ring.
The name of the substituent is joined to that of the parent, and the locant is attached to that with a hyphen.
The generic IUPAC name is bromobenzoic acid.
There are three isomers of benzoic acid — 2-bromobenzoic acid, 3-bromobenzoic acid, and 4-bromobenzoic acid — so you must always specify which one you mean.
