mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest .
<u>Step-by-step explanation:</u>
Here we have , mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for the same length of time, We need to find how long must he leave it to gain 5600 in interest . Let's find out:
Let mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8% for time x months , So total interest gain is 5600 i.e.
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Therefore , mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest .
Answer:
Y = [-6 6 6 -6]
Step-by-step explanation:
From the given matrices
If X - 2Y = Z
b - 2c = a ... 1
a -2d = c ...2
4+2a = 16.... 3
a + 2b = b .... 4
From3 ;
2a = 16-4
2a = 12
a = 6
From 4;
a + 2b - b = 0
a+b = 0
a = -b
6 = -b
b = -6
From1;
b - 2c = a
-6 - 2c = 6
-2c = 12
c = -6
also
a - 2d = c
6-2d = -6
-2d = -6-6
-2d = -12
d = 6
Hence the matrices Y = [-6 6 6 -6]
We solve 6 + 4
6 + 4 = 10.
Square root of 10:
<span>The square root of 10 is a periodic decimal (decimal that has infinite decimals, worth the redundancy)
What is that periodic decimal?
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<u>
REGARDS!</u>
Answer:
Step-by-step explanation:
2 + m
Rewrite with variable first.
m + 2
m + 2
Can’t be simplified further.
m - (-2)
Distribute negative sign.
m + 2
-2-m
Rewrite with variable first.
-m - 2
The last expression is not equivalent to m+2.