Sodium oxide contains Na+ ions and O2- ions. Give the formula of sodium oxide

Chemistry

1 answer:

mixer [17]3 years ago

8 0

To be honest, I learned this in school so I'll tell you XD

The formula of sodium oxide is Na2O

You might be interested in

Riddle: What has to be broken before you can use it?

pickupchik [31]

Answer:

An egg will be your ans because it needs to be broken before we can cook it or use it for making other delicases

Explanation:

Hope it helps 

4 0

2 years ago

The piece of iron that miguel measured had a mass of 51.1 g and a volume of 6.63 cm 3 . what did miguel calculate to be the dens

likoan [24]

Given:
Mass, m = 51.1 g
Volume, V = 6.63 cm³

By definition,
Density = Mass/Volume
= (51.1 g)/(6.63 cm³)
= 7.7074 g/cm³

In SI units,
Density = (7.7074 g/cm³)*(10⁻³ kg/g)*(10² cm/m)³
= 7707.4 kg/m³

Answer: 7.707 g/cm³ or 7707.4 kg/m³

4 0

3 years ago

Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce

Iteru [2.4K]

Answer:

10.85 g of water

Explanation:

First we write the balanced chemical equation

$3NO_{2} +H_{2}O -->2HNO_{3} +NO$

Then we calculate the number of moles of nitric acid produced

n(HNO3) = $\frac{mass}{molar mass} =\frac{75.9g}{63.02g/mol}=1.2044 mol$

According to the balanced equation, water needed in moles is always half the number of moles of HNO3 produced. So since we will produce 1.2044 mol of HNO3, we will need 0.6022 mol of water. Now to calculate what mass that is:

mass(water)=number of moles*molar mass=0.6022mol*18.02g/mol=10.85g

5 0

3 years ago

Suppose you have a 2.0 molar solution of sodium hydroxide (naoh), and you need 65 ml of 0.6 molar naoh. how should you make this

nalin [4]

The given molarity of sodium hydroxide solution = 2.0 M

The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH

Converting 65 mL to L:

$65mL*\frac{1L}{1000mL} =0.065L$