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inysia [295]
3 years ago
10

6. Balance the following equations (3 points)

Chemistry
2 answers:
Schach [20]3 years ago
8 0

a.  FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

b. 2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

c. Fe2O3 + 3 H2 = 2 Fe + 3 H2O

SSSSS [86.1K]3 years ago
6 0

The answer is

a.  FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

b. 2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

c. Fe2O3 + 3 H2 = 2 Fe + 3 H2O


To balance equations you basically have to make sure each element has an equal amount or number on each side of the equation. If you need more help understanding this, feel free to ask.

:)

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<u>Answer:</u>

<u>Plasmas of great interest to scientists or manufacturers as</u>

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3 years ago
How are metal atoms arranged according to metallic bonding ?
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2 years ago
How could we increase the strength of a solenoid?
12345 [234]

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2) increasing the number of coils in the solenoid; and.

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8 0
3 years ago
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3 years ago
Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many
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Answer : The amount of formaldehyde permissible are, 5.4\times 10^{-6}g

Explanation : Given,

Density of air = 1.2kg/m^3=1.2g/L     (1kg/m^3=1g/L)

First we have to calculate the mass of air.

\text{Mass of air}=\text{Density of air}\times \text{Volume of air}

\text{Mass of air}=1.2g/L\times 6.0L

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Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

Amount of formaldehyde in 7.2 g of formaldehyde = 7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

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Thus, the amount of formaldehyde permissible are, 5.4\times 10^{-6}g

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3 years ago
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