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I am Lyosha [343]
3 years ago
14

A sample of the compound magnesium oxide is synthesized as follows. 60. g of magnesium is burned and produces 100. g of magnesiu

m oxide, indicating that the magnesium combined with 40. g of oxygen in the air. If 30. g of magnesium had been used, what mass of oxygen would have combined with it? What law of chemistry is used in solving this problem?
Chemistry
1 answer:
Inga [223]3 years ago
5 0

Answer:

30 g of magnesium would be combined with 20 g of oxygen. The law used solving this problem is the Lavoisier Law of conservation of mass.

Explanation:

If 60 g of magnesium combines with 40 g of oxygen to make 100 g of magnesium oxide, then 30 g of magnesium will combine with 20 g of oxygen to make 50 g of magnesium oxide.

This happens because in a chemical reaction there is no creation or descruction of atoms, only a rearrangement. Therefore, the mass of reactants should be equal to the mass of products.

The following equation represents the proportions of the substances:

Mg + 1/2O₂ → MgO

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Answer: Photosynthesis

Explanation:

<em>The process of photosynthesis</em> is used to help make food for plants. The inputs are sunlight, water (H2O), and carbon dioxide (CO2). Then the outputs are glucose (C6H12O6) which is food, and oxygen (O2) is released.

I hope this helps :)

4 0
3 years ago
What is an example of an electrolyte solution?
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Answer:

nacl with water

they are capable of conducting electricity

3 0
3 years ago
An acid is:
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An acid is a proton donor
5 0
3 years ago
What is the volume of one mole of any gas at STP?
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7 0
4 years ago
Gallium has two naturally occurring isotopes: 69ga with a mass of 68.9256 amu and a natural abundance of 60.11% and 71ga. use th
Nataly [62]

There are two naturally occurring isotopes of gallium:  mass of Ga-69 isotope is 68.9256 amu and its percentage abundance is 60.11%, let the mass of other isotope that is Ga-71 be X, the percentage abundance can be calculated as:

%Ga-71=100-60.11=39.89%

Atomic mass of an element is calculated by taking sum of atomic masses of its isotopes multiplied by their percentage abundance.

Thus, in this case:

Atomic mass= m(Ga-69)×%(Ga-69)+X×%(Ga-71)

From the periodic table, atomic mass of Ga is 69.723 amu.

Putting the values,

69.723 amu=(68.9256 amu)(\frac{60.11}{100})+X(\frac{39.89}{100})

Thus,

69.723 amu=41.4312 amu+X(\frac{39.89}{100})

Rearranging,

X=\frac{69.723 amu-41.4312 amu}{0.3989}=70.9246 amu

Therefore, mass of Ga-71 isotope is 70.9246 amu.

7 0
3 years ago
Read 2 more answers
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