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frutty [35]
3 years ago
9

What is the basic principle that is used during the during the structures of compounds​

Chemistry
1 answer:
levacccp [35]3 years ago
6 0

Answer:

For petrochemical products, most of the petrochemical products are hydrocarbons and their derivatives natural gas, kerosene, gasoline, etc.

Resonance of molecules is the most stable structure of molecules and most stable structure is its middle form among all the resonance structures. This same phenomenon is used in swings.

Explanation:

nag search po ako XD

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trapecia [35]

Th actual yield of the reaction is 24.86 g

We'll begin by calculating the theoretical yield of the reaction.

2Na + Cl₂ → 2NaCl

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced = 2 × 58.5 = 117 g

From the balanced equation above,

46 g of Na reacted to produce 117 g of NaCl.

Therefore,

11.5 g of Na will react to produce = (11.5 × 117) / 46 = 29.25 g of NaCl.

Thus, the theoretical yield of NaCl is 29.25 g.

Finally, we shall determine the actual yield of NaCl.

  • Percentage yield = 85%
  • Theoretical yield = 29.25 g
  • Actual yield =?

Actual yield = Percent yield × Theoretical yield

Actual yield = 85% × 29.25

Actual yield = 0.85 × 29.25 g

Actual yield = 24.86 g

Learn more about stoichiometry: brainly.com/question/25899385

7 0
3 years ago
How many liters of hydrogen gas I needed to react with CS2 to produce 2.5 L of CH4 At STP
olchik [2.2K]

Answer:

9.8 L

Explanation:

The reaction that takes place is:

  • 4H₂(g) + CS₂(g) → CH₄(g)+ 2H₂S(g)

At STP, 1 mol of any gas occupies 22.4 L.

We <u>calculate how many moles are there in 2.5 L of CH₄ at STP</u>:

  • 2.5 L ÷ 22.4 L/mol = 0.11 mol CH₄

Then we <u>convert CH₄ moles into H₂ moles</u>, using the<em> stoichiometric coefficients of the reaction</em>:

  • 0.11 mol CH₄ * \frac{4molH_2}{1molCH_4} = 0.44 mol H₂

Finally we <u>calculate the volume that 0.44 moles of H₂ would occupy at STP</u>:

  • 0.44 mol * 22.4 L/mol = 9.8 L
8 0
3 years ago
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