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Akimi4 [234]
4 years ago
13

why does every human measurement have uncertainty associated with it? Why must we manage the uncertainty during calculations?

Chemistry
1 answer:
dimulka [17.4K]4 years ago
3 0
Because there are many numbers of the human measurement . we must manage the uncertainly doing calculations because we can know what we are calculating.
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Visible light is an example of
Svetradugi [14.3K]

Answer:

electromagnetic energy.

Explanation:

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3 0
3 years ago
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When 7.94 g of xylene was added to 132.5 g of cyclohexane, the freezing point of the solution was -4.9oC. What is the molar mass
777dan777 [17]
Answer is: molar mass of xylene 106,18 g/mol.
m(xylene) = 7,94 g.
m(cyclohexane) = 132,5 g.
T (solution) = - 4,9 °C.
Tf(cyclohexane) = 6,5 °C, frezing point.
Kf(cyclohexane) = 20,2 K·kg/mol; cryoscopic constant.
ΔT(solution) = 6,5°C - (-4,9°C) = 11,4°C = 11,4 K.
M(xylene) = Kf · m(xylene) ÷ m(cyclohexane) · ΔT(solution).
M(xylene) = 20,2 K·kg/mol · 7,94 g ÷ 0,1325 kg · 11,4 K.
M(xylene) = 106,18 g/mol.


6 0
3 years ago
Calculate ΔGrxn for this equation, rounding your answer to the nearest whole number. CaCO3(s) → CaO(s) + CO2(g) ΔGf,CaCO3 = −1,1
FrozenT [24]

Answer: \Delta G_{rxn} for the given reaction is 130.19kJ/mol

Explanation:

To Calculate the \Delta G_{rxn}, we use the formula:

\Delta G_{rxn}=\Delta G_{products}-\Delta G_{reactants}

For the given chemical reaction:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

We are given:

\Delta G_{CaCO_3}=-1128.76kJ/mol\\\Delta G_{CaO}=-604.17kJ/mol\\\Delta G_{CO_2}=-394.4kJ/mol

Now, to calculate \Delta G_{rxn}, we put the values in the above equation:

\Delta G_{rxn}=(\Delta G_{CaO}+\Delta G_{CO_2})-\Delta G_{CaCO_3}

\Delta G_{reaction}=(-604.17-394.4)-(-1128.76)kJ/mol\\\Delta G_{reaction}=130.19kJ/mol

As, the value of \Delta G_{reaction} comes out to be positive, the reaction is said to be non-spontaneous reaction.

3 0
3 years ago
4. Again, have someone hold the mirror for you, slowly move at least 3 m away
faltersainse [42]
Closer is bigger................
8 0
3 years ago
Mass of oxygen gas needed to burn 37.5g of wax
Slav-nsk [51]
Answer is: mass oxygen is 129,28 grams.
Chemical reaction: 2C₁₈H₃₈ + 55O₂ → 36CO₂ + 38H₂O.
m(C₁₈H₃₈) = 37,5 g.
n(C₁₈H₃₈) = m(C₁₈H₃₈) ÷ M(C₁₈H₃₈).
n(C₁₈H₃₈) = 37,5 g ÷ 254 g/mol.
n(C₁₈H₃₈) = 0,147 mol.
From chemical reaction: n(C₁₈H₃₈) : n(O₂) = 2 : 55.
n(O₂) = 4,04 mol.
m(O₂) = 4,04 mol · 32 g/mol.
m(O₂) = 129,28 g.
6 0
4 years ago
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