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Naddik [55]
2 years ago
6

A rectangle has vertices at these coordinates. (−6, 3), (−6, 5), (2, 3) What are the coordinates of the fourth vertex of the rec

tangle?
Mathematics
1 answer:
Anna35 [415]2 years ago
7 0

Answer:

(2, 5).

Step-by-step explanation:

The length of the line joining the first 2 points = (5 - 3) = 2 units. This is a vertical line because the 2 x coordinates  ( -6 and - 6) are equal.

The line joining ( -6 , 3) and (2 , 3) is horizontal and is 2 - -6 = 8 units long.

Because we have a rectangle the point we need to find must have x coordinate of 2 and the y coordinate will be 2 more than the y coordinate 3.

.So it is  (2, 5),

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What is the percent of change if the price changes from $150 to $100? Round to the nearest whole percent if necessary.
lisabon 2012 [21]

Answer:

Percentual change= 33.33% decrease

Step-by-step explanation:

Giving the following information:

Present value (PV)= $150

Future value (FV)= $100

<u>To calculate the percentual change, we need to use the following formula:</u>

Percentual change= [(PV - FV) / PV]*100

Percentual change= [(150 - 100) / 150]*1''

Percentual change= 0.3333*100

Percentual change= 33.33% decrease

4 0
3 years ago
Solve 10 + 6(–9 – 4x) = 10(x – 12) + 8
Leviafan [203]
1. 10 + 6(-9-4x)=10(x-12)+8
2.10 +-45-24x=10x-120+8
3.10 +7 = 34x -120 +8
4.17=34x-120+8
5.17=34x +128
6. 34x=115
7.x= 0.29565217391
8 0
3 years ago
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What is 9713 rounded to the place value
Akimi4 [234]
It could be 10000,9800,or 9710
6 0
3 years ago
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0
3 years ago
Round off 7284 to 1sf​
AVprozaik [17]

Answer:

7000

Step-by-step explanation:

This is because when you round to the significant figure, you basically look at any digits at the start of the number, which isn't zero. In this case, it would be in the thousands place 7284. So you round 7284 to the nearest thousands, which, would be 7000

6 0
3 years ago
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